110KV35KV變電站繼電保護(hù)整定計(jì)算書(shū)

10〔一、XX變繼電保護(hù)整定計(jì)算書(shū)XX變35KV母線短路阻抗最大運(yùn)行方式下為0.24750.3708，20230KVA20230KVA變壓器運(yùn)行分列運(yùn)行。荷，故計(jì)算定值時(shí)按一路進(jìn)線及一臺(tái)變壓器運(yùn)行計(jì)算。一、繪制等值電路圖、繪制系統(tǒng)接線圖〔見(jiàn)附圖〕選取基準(zhǔn)容量Sb=100MVA選取短路點(diǎn)所在母線的平均電壓為基準(zhǔn)電壓即：計(jì)算K1點(diǎn)時(shí)，選取Ub1=37KVK2點(diǎn)時(shí)，選取Ub2=6.3KV計(jì)算K6302 K6412-點(diǎn)時(shí)，選取Ub3=6.3KV二、計(jì)算各元件的電抗標(biāo)么值SU、I、X——一以基準(zhǔn)量表示的容量MA、電壓(KV(KAΩ)j j j jSe----額定容量(MA)； Ud%----阻抗電壓百分?jǐn)?shù)； Xd% 超瞬變電抗百分?jǐn)?shù)；XO-----每千米電抗(Ω/km)； Up-----平均額定電壓(KV)； X% 電抗百分?jǐn)?shù)；L 線路長(zhǎng)度(km)；1、1#主變：X1=Ud%/100*Sj/Se=7.85/100*100/20=0.39252#主變：X2=Ud%/100*Sj/Se=8.06/100*100/20=0.4032、6KV線路：(集配站6302線路) X3線=XO*L*Sj/Up2=0.4*3.2*100/6.32=3.225X3纜=XO*L*Sj/Up2=0.08*0.19*100/6.32=0.038X3=X3線+X3纜=3.225+0.038=3.263(旭飛公司6303線路) X4線=XO*L*Sj/Up2=0.353*2.2*100/6.32=1.9567X4纜=XO*L*Sj/Up2=0.08*0.1*100/6.32=0.0202X4=X4線+X4纜=1.9567+0.0202=1.9769(恒興公司6304線路) X5線=XO*L*Sj/Up2=0.347*4*100/6.32=3.4971X5纜=XO*L*Sj/Up2=0.08*0.15*100/6.32=0.0302X5=X5線+X5纜=3.4971+0.0302=3.5273(金能公司6305線路) X6線=XO*L*Sj/Up2=0.347*4.6*100/6.32=4.0217X6纜=XO*L*Sj/Up2=0.08*0.15*100/6.32=0.0302X6=X6線+X6纜=4.0217+0.0302=4.0519〔一采區(qū)Ⅰ路線路〕6306線路為相分裂架設(shè)，故：線 X7 =XO*L*Sj/U2/2=0.333*2.6*100/6.32線 纜 X7 =XO*L*Sj/U2/2=0.08*0.4*100/6.32/2=0.0403X7=纜 線 纜線 (環(huán)興磁場(chǎng)6307線路) X8 =XO*L*Sj/U2=0.347*4*100/6.32線 纜 X8 =XO*L*Sj/U2=0.08*0.17*100/6.32=0.0171X8=纜 線 纜線 (乳化車(chē)間6308線路) X9 =XO*L*Sj/U2=0.347*6.4*100/6.32線 纜 X9 =XO*L*Sj/U2=0.08*0.07*100/6.32=0.0141X9=纜 線 纜p〔6309線路〕X10〔架空〕=XO*L*Sj/U2/2=0.333*1.7*100/6.32=1.4263pX 〔電纜〕=X LS/U2/2=0.080.24100/6.32=0.048410 O* * j p * *10 X10=X 〔架空〕+X 〔電纜〕=1.426310 〔1#動(dòng)力變6311線路〕

〔電纜〕=X LS/U2/2=0.080.22100/6.32=0.044311 O* * j p * *(三泵房6402線路) 因6402線路為電纜線路，故：XO為0.08Ω/kmX12=XO*L*Sj/Up2=0.08*0.4*100/6.32=0.0806(深井專(zhuān)線6403線路) X13線=XO*L*Sj/Up2=0.353*2.5*100/6.32=2.2235X13纜=XO*L*Sj/Up2=0.08*0.5*100/6.32=0.1008X13=X13線+X13纜=2.2235+0.1008=2.3243(眾元洗煤廠6404線路) 因6404線路為電纜線路，故：XO為0.08Ω/kmX14=XO*L*Sj/Up2=0.08*0.5*100/6.32=0.1008〔一采區(qū)Ⅱ路線路〕6406線路為相分裂架設(shè)，故：X15線=XO*L*Sj/Up2/2=0.325*3.6*100/6.32/2=1.4739X15纜=XO*L*Sj/Up2/2=0.08*0.32*100/6.32/2=0.0302X15=X15線+X15纜=1.4739+0.03225=1.5062(石康鑄造6407線路) X16線=XO*L*Sj/Up2=0.365*0.3*100/6.32=0.2759X16纜=XO*L*Sj/Up2=0.08*0.15*100/6.32=0.2653X16=X16線+X16纜=0.2759+0.2653=0.5412(化工廠6408線路) X17線=XO*L*Sj/Up2=0.347*8.4*100/6.32=7.3439X17纜=XO*L*Sj/Up2=0.08*0.11*100/6.32=0.02217X17=X17線+X17纜=7.3439+0.02217=7.366線 (四泵房6409線路) X18 =XO*L*Sj/U2=0.347*4*100/6.32線 纜 X18 =XO*L*Sj/U2=0.08*0.15*100/6.32=0.0302X18=纜 線 纜線 (然爾特6410線路) X19 =XO*L*Sj/U2=0.325*2.1*100/6.32線 纜 X19 =XO*L*Sj/U2=0.08*0.3/2*100/6.32=0.030X19=纜 線 纜線 (三礦物業(yè)6412線路) X20 =XO*L*Sj/U2=0.353*1.8*100/6.32線 纜 X20 =XO*L*Sj/U2=0.08*0.1*100/6.32=0.0202X20=纜 線 纜三、計(jì)算K2點(diǎn)的短路參數(shù)〔K2點(diǎn)前的總阻抗及短路電流〕1、最大運(yùn)行方式下：XK2max=0.24756+0.3925=0.64006最小運(yùn)行方式下：XK2min=0.37084+0.3925=0.763342、k2點(diǎn)的超瞬變短路電流I”：(用來(lái)作繼電保護(hù)的整定計(jì)算和校驗(yàn)斷路器的斷流量)3依據(jù)：I”k2=Ij/XK2max 設(shè)基準(zhǔn)容量為：Sj=100MVA33且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p33I”k2=Ij/XK2max=9.165/0.64006=14.319〔KA〕33同理：I” =I/X

且基準(zhǔn)電流為：I=S/ U=100/

*6.3=9.165〔KA〕k2 j

K2min

j j pI”k2=Ij/XK2min=9.165/0.76334=12.006〔KA〕四、計(jì)算末端K6302-----K6412點(diǎn)的短路參數(shù)〔K6302 K6412各點(diǎn)的阻抗及三相短路電流〕31、∵ K6302max=XK2max+X3=0.64006+3.263=3.90306K6302min=XK2min+X3=0.7634+3.263=4.026433且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6302max=Ij/K6302max=9.165/3.90306=2.349〔KA〕I”6302min=Ij/K6302min=9.165/4.0264=2.277〔KA〕32、K6303max=XK2max+X4=0.64006+1.9769=2.617K6303min=XK2min+X4=0.76334+1.9769=2.74033且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6303max=Ij/K6303max=9.165/2.617=3.502〔KA〕I”6303min=Ij/K6303min=9.165/2.74=3.345〔KA〕3、K6304max=XK2max+X5=0.64006+3.5273=4.1673K6304min=XK2min+X5=0.7634+3.5273=4.29133且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6304max=Ij/K6304max=9.165/4.167=2.199〔KA〕I”6304min=Ij/K6304min=9.165/4.291=2.136〔KA〕34、K6305max=XK2max+X6=0.64006+4.0519=4.5755K6305min=XK2min+X6=0.76334+4.0519=4.699633且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6305max=Ij/K6305max=9.165/4.5755=2.003〔KA〕I”6305min=Ij/K6305min=9.165/4.6996=1.950〔KA〕35、K6306max=XK2max+X7=0.64006+1.1313=1.771K6306min=XK2min+X7=0.76334+1.1313=1.89533且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6306max=Ij/K6306max=9.165/1.771=5.175〔KA〕I”6306min=Ij/K6306min=9.165/1.895=4.836〔KA〕36、K6307max=XK2max+X8=0.64006+3.5142=4.154K6307min=XK2min+X8=0.76334+3.5142=4.27833且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6307max=Ij/K6307max=9.165/4.154=2.206〔KA〕I”6307min=Ij/K6307min=9.165/4.278=2.142〔KA〕37、K6308max=XK2max+X9=0.63006+5.6095=6.2396K6308min=XK2min+X9=0.76334+5.6095=6.372833且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6308max=Ij/K6308max=9.165/6.2396=1.469〔KA〕I”6308min=Ij/K6308min=9.165/6.3728=1.438〔KA〕38、K6309max=XK2max+X10=0.64006+1.4747=2.11476K6309min=XK2min+X10=0.76334+1.4747=2.2380433且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6309max=Ij/K6306max=9.165/2.11476=4.334〔KA〕I”6309min=Ij/K6306min=9.165/2.23804=4.095〔KA〕9、K6311max=XK2max+X11=0.64006+0.0443=0.6844K6311min=XK2min+X11=0.76334+0.0443=0.807633且基準(zhǔn)電流為：I=S/ U=100/33

*6.3=9.165〔KA〕j j p∴I”6311max=Ij/K6311max=9.165/0.6844=13.391〔KA〕I”6311min=Ij/K6311min=9.165/0.8076=11.348〔KA〕310、K6402max=XK2max+X12=0.64006+0.0806=0.7207K6402min=XK2min+X12=0.76334+0.0806=0.843933且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6402max=Ij/K6402max=9.165/0.7207=12.717〔KA〕I”6402min=Ij/K64028min=9.165/0.8439=10.860〔KA〕311、K6403max=XK2max+X13=0.64006+2.3243=2.964K6403min=XK2min+X13=0.76334+2.3243=3.08833且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6403max=Ij/K6403max=9.165/2.964=3.092〔KA〕I”6403min=Ij/K6403min=9.165/3.088=2.968〔KA〕312、K6404max=XK2max+X14=0.64006+0.1008=0.7409K6404min=XK2min+X14=0.76334+0.1008=0.864133且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6404max=Ij/K6404max=9.165/0.7409=12.370〔KA〕I”6404min=Ij/K6404min=9.165/0.8641=10.606〔KA〕313、K6406max=XK2max+X15=0.64006+1.5062=2.146K6406min=XK2min+X15=0.76334+1.5062=2.269533且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6406max=Ij/K6406max=9.165/2.146=4.271〔KA〕I”6406min=Ij/K6406min=9.165/2.2696=4.038〔KA〕314、K6407max=XK2max+X16=0.64006+0.5412=1.181K6407min=XK2min+X16=0.76334+0.5412=1.30533且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6407max=Ij/K6407max=9.165/1.181=7.760〔KA〕I”6407min=Ij/K6407min=9.165/1.305=7.023〔KA〕15、K6408max=XK2max+X17=0.64006+7.366=8.0063K6408min=XK2min+X17=0.76334+7.366=8.12933且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6408max=Ij/K6408max=9.165/8.006=1.145〔KA〕I”6408min=Ij/K6408min=9.165/8.129=1.127〔KA〕16、K6409max=XK2max+X18=0.64006+3.5273=4.1673K6409min=XK2min+X18=0.76334+3.5273=4.29133且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6409max=Ij/K6409max=9.165/4.167=2.199〔KA〕I”6409min=Ij/K6409min=9.165/4.291=2.136〔KA〕17、K6410max=XK2max+X19=0.64006+3.5273=4.1673K6410min=XK2min+X19=0.76334+3.5273=4.29133且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6410max=Ij/K6410max=9.165/4.167=2.199〔KA〕I”6410min=Ij/K6410min=9.165/4.291=2.136〔KA〕318、K6412max=XK2max+X20=0.64006+1.6212=2.261K6412min=XK2min+X20=0.76334+1.6212=2.38533且基準(zhǔn)電流為：I=S/ U=100/3

*6.3=9.165〔KA〕j j p∴I”6412max=Ij/K6412max=9.165/2.261=4.054〔KA〕I”6412min=Ij/K6412min=9.165/2.385=3.843〔KA〕五、整定計(jì)算速斷動(dòng)作電流整定公式：Idzj=KkKjxI”d2max/n1式中： dzj----瞬時(shí)電流速斷保護(hù)裝置的動(dòng)作電流整定值A(chǔ)；”d2max 最大運(yùn)行方式下線路末端三相短路超瞬變電流A；Kk-----1.2；Kjx 1；n1 電流互感器變比；過(guò)流淌作電流整定公式：Idzj=KkKjxIgh/Khn1式中： Idzj=KkKjxIgh/Khn1式中： dzj----保護(hù)裝置的動(dòng)作電流整定值〔；gh線路的最大負(fù)荷電流A；Kk 1.2；h 繼電器返回系數(shù)，取1.〔微機(jī)型；Kjx 1；n1 電流互感器變比；繼電保護(hù)整定值計(jì)算如下：1、集配站6302〔CT變比：400/5〕31、速斷動(dòng)作電流dzj=kjx”d2max/1=1.2*1*2349/80=3A〕 〔取25〕32、帶時(shí)限過(guò)電流淌作電流：∵Igh=407(A) 依據(jù)I=P/

U*COS?=〔800+630〕3/35*800/

*6.3*0.9=146 因6302 線路所帶最大變壓器為800KVA，啟動(dòng)電流為3*6.3*0.9=4073∴Idzj=KkKjxIgh/Khn1=1.2*1*407/1*80=6.1〔A〕 3、靈敏系數(shù)校驗(yàn)、電流速斷保護(hù)靈敏度校驗(yàn)：Km=KmxdI”d1min/Idz≥2 依據(jù)《繼電保護(hù)及二次回路速查速算手冊(cè)》Km 靈敏系數(shù)；Kmxd 0.866min 最小運(yùn)行方式下線路始端三相短路穩(wěn)態(tài)電流〔A〕Idz-----保護(hù)裝置一次動(dòng)作電流〔A〕Idz=Idzjn1/Kjx依據(jù)：Km=KmxdId1min/Idz=0.866*12023/25*80/1=5.2>22=Kmxd”d2min/dz≥1.5Kmxd 0.866min 最小運(yùn)行方式下線路末端三相短路超瞬變電流〔A〕Idz-----保護(hù)裝置一次動(dòng)作點(diǎn)流〔A〕Idz=Idzjn1/Kjx依據(jù)：Km=KmxdId2min/Idz=0.866*2277/6*80/1=4.1>1.54)、時(shí)限整定：63020.8S2、旭飛公司6303〔CT變比：200/5〕1、速斷動(dòng)作電流dzj=kjx”d2max/1=1.2*1*3502/40=105.0A〕 〔取45〕2、帶時(shí)限過(guò)電流淌作電流：g=162(A) 依據(jù)區(qū)變實(shí)際運(yùn)行負(fù)荷得出的值∴Idzj=KkKjxIgh/Khn1=1.2*1*162/1*40=4.8 〔A〕 〔6A〕3、靈敏系數(shù)校驗(yàn)(1、電流速斷保護(hù)靈敏度校驗(yàn)=Kmxd”d1min/Idz≥2 依據(jù)《繼電保護(hù)及二次回速查速算手冊(cè)》依據(jù)：Km=KmxdId1min/Idz=0.866*12023/45*40/1=5.7>22=Kmxd”d2n依據(jù)：Km=KmxdId2min/Idz=0.866*3345/6*40/1=12.1>1.54)、時(shí)限整定：63030.8S3、恒興公司6304〔CT變比：800/5〕1、速斷動(dòng)作電流dzj=kjx”d2max/1=1.2*1*2199/160=16.4A〕 〔取11〕2、帶時(shí)限過(guò)電流淌作電流：g=178(A) 依據(jù)區(qū)變實(shí)際運(yùn)行負(fù)荷得出的值∴Idzj=KkKjxIgh/Khn1=1.2*1*178/1*160=1.335 〔A〕 〔2.3A〕3、靈敏系數(shù)校驗(yàn)(1、電流速斷保護(hù)靈敏度校驗(yàn)=Kmxd”d1min/Idz≥2 依據(jù)《繼電保護(hù)及二次回速查速算手冊(cè)》依據(jù)：Km=KmxdId1min/Idz=0.866*12023/11*160/1=5.91>22=Kmxd”d2n依據(jù)：Km=KmxdId2min/Idz=0.866*2136/2.3*160/1=5>1.54)、時(shí)限整定：63040.8S4、金能公司6305〔CT變比：300/5〕1、速斷動(dòng)作電流dzj=kjx”d2max/1=1.2*1*2023/60=4A〕 〔取26〕2、帶時(shí)限過(guò)電流淌作電流：g=120(A) 依據(jù)區(qū)變實(shí)際運(yùn)行負(fù)荷得出的值∴Idzj=KkKjxIgh/Khn1=1.2*1*120/1*60=2.4 〔A〕 〔5A〕3、靈敏系數(shù)校驗(yàn)(1、電流速斷保護(hù)靈敏度校驗(yàn)=Kmxd”d1min/Idz≥2 依據(jù)《繼電保護(hù)及二次回速查速算手冊(cè)》依據(jù)：Km=KmxdId1min/Idz=0.866*12023/26*60/1=6.6>22=Kmxd”d2n依據(jù)：Km=KmxdId2min/Idz=0.866*195/5*60/1=5.6>1.54)、時(shí)限整定：63050.8S5、一采區(qū)Ⅰ路6306〔CT變比：1000/5〕1、速斷動(dòng)作電流dzj=kjx”d2max/1=1.2*1*5175/200=3A〕 〔取28〕2、帶時(shí)限過(guò)電流淌作電流：g=1724(A) 依據(jù)一采區(qū)600水平要上綜采工作面，金公司機(jī)械動(dòng)力部報(bào)來(lái)需增加負(fù)荷為：1724A.∴Idzj=KkKjxIgh/Khn1=1.2*1*1724/1*200=10.3〔A〕 〔取因要與一采變協(xié)作故取11.8A〕3、靈敏系數(shù)校驗(yàn)(1、電流速斷保護(hù)靈敏度校驗(yàn)=Kmxd”d1min/Idz≥2 依據(jù)《繼電保護(hù)及二次回速查速算手冊(cè)》依據(jù)：Km=KmxdId1min/Idz=0.866*12023/28*200/1=1.8<22=Kmxd”d2n依據(jù)：Km=KmxdId2min/Idz=0.866*4836/11.8*200/1=1.8>1.54)、時(shí)限整定：63060.8S6、環(huán)興磁廠6307〔CT變比：300/5〕1、速斷動(dòng)作電流dzj=kjx”d2max/1=1.2*1*2206/60=44.〕 〔取26〕2、帶時(shí)限過(guò)電流淌作電流：g=250(A) 依據(jù)區(qū)變實(shí)際運(yùn)行負(fù)荷得出的值∴Idzj=KkKjxIgh/Khn1=1.2*1*250/1*60=5〔A〕 〔7A〕3、靈敏系數(shù)校驗(yàn)(1、電流速斷保護(hù)靈敏度校驗(yàn)=Kmxd”d1min/Idz≥2 依據(jù)《繼電保護(hù)及二次回速查速算手冊(cè)》依據(jù)：Km=KmxdId1min/Idz=0.866*12023/26*60/1=6.7>22=Kmxd”d2n依據(jù)：Km=KmxdId2min/Idz=0.866*2142/7*60/1=4.4>1.54)、時(shí)限整定：63070.8S7、乳化車(chē)間6308〔CT變比：300/5〕1、速斷動(dòng)作電流dzj=kjx”d2max/1=1.2*1*1469/60=29.3〕 〔取20〕2、帶時(shí)限過(guò)電流淌作電流：g=133(A) 依據(jù)區(qū)變實(shí)際運(yùn)行負(fù)荷得出的值∴Idzj=KkKjxIgh/Khn1=1.2*1*133/1*60=2.7〔A〕 〔5A〕3、靈敏系數(shù)校驗(yàn)(1、電流速斷保護(hù)靈敏度校驗(yàn)=Kmxd”d1min/Idz≥2 依據(jù)《繼電保護(hù)及二次回速查速算手冊(cè)》依據(jù)：Km=KmxdId1min/Idz=0.866*12023/20*60/1=8.6>22=Kmxd”d2n依據(jù)：Km=KmxdId2min/Idz=0.866*1438/5*60/1=4.1>1.54)、時(shí)限整定：63080.8S8、眾元三分公司6309〔CT變比：400/5〕1、速斷動(dòng)作電流dzj=kjx”d2max/1=1.2*1*4334/80=6A〕 〔取29〕2帶時(shí)限過(guò)電流淌作電流∵g=2830/1.732/6.3=259(A) 依據(jù)區(qū)變實(shí)際運(yùn)行負(fù)荷得出的值∴Idzj=KkKjxIgh/Khn1=1.2*1*259/0.85*80=4.5〔A〕 3、靈敏系數(shù)校驗(yàn)(1、電流速斷保護(hù)靈敏度校驗(yàn)=Kmxd”d1min/Idz≥2 依據(jù)《繼電保護(hù)及二次回速查速算手冊(cè)》依據(jù)：Km=KmxdId1min/Idz=0.866*12023/29*80/1=4.48>22=Kmxd”d2n依據(jù)：Km=KmxdId2min/Idz=0.866*4095/5*80/1=8.8>1.54)、時(shí)限整定：63090.8S91#動(dòng)力變6311〔CT變比：200/5〕31、速斷動(dòng)作電流dzj=kjx”d2max/1=1.2*1*13391/40=401.7A〕 〔取30〕32g=P/變實(shí)際運(yùn)行負(fù)荷得出的值

U*COS?=100/1.732*6.3*0.9=10.2〔A) 依據(jù)區(qū)∴Idzj=KkKjxIgh/Khn1=1.2*1*10.2/1*40=0.306〔A〕 0.7A〕3、靈敏系數(shù)校驗(yàn)(1、電流速斷保護(hù)靈敏度校驗(yàn)=Kmxd”d1min/Idz≥2 依據(jù)《繼電保護(hù)及二次回速查速算手冊(cè)》依據(jù)：Km=KmxdId1min/Idz=0.866*12023/30*40/1=8.6>22=Kmxd”d2n依據(jù)：Km=KmxdI”d2min/Idz=0.866*11348/0.7*40/1=350.98>1.54)、時(shí)限整定：63090.8S10、三泵房6402〔CT變比：100/5〕1、速斷動(dòng)作電流dzj=kjx”d2max/1=1.2*1*12717/20=76〕 〔取90〕2、帶時(shí)限過(guò)電流淌作電流：g=70(A) 依據(jù)區(qū)變實(shí)際運(yùn)行負(fù)荷得出的值∴Idzj=KkKjxIgh/Khn1=1.2*1*70/1*20=4.2 〔A〕 〔5A〕3、靈敏系數(shù)校驗(yàn)(1、電流速斷保護(hù)靈敏度校驗(yàn)=Kmxd”d1min/Idz≥2 依據(jù)《繼電保護(hù)及二次回速查速算手冊(cè)》依據(jù)：Km=KmxdId1min/Idz=0.866*12023/90*20/1=5.7>22=Kmxd”d2n依據(jù)：Km=KmxdId2min/Idz=0.866*10860/5*20/1=94>1.54)、時(shí)限整定：64020.8S11、深井專(zhuān)線6403〔CT變比：500/5〕1、速斷動(dòng)作電流dzj=kjx”d2max/1=1.2*1*3092/100=37.〕 〔取16〕2、帶時(shí)限過(guò)電流淌作電流：g=238(A) 依據(jù)區(qū)變實(shí)際運(yùn)行負(fù)荷得出的值∴Idzj=KkKjxIgh/Khn1=1.2*1*238/1*100=2.86 〔A〕 〔5A〕3、靈敏系數(shù)校驗(yàn)(1、電流速斷保護(hù)靈敏度校驗(yàn)=Kmxd”d1min/Idz≥2 依據(jù)《繼電保護(hù)及二次回速查速算手冊(cè)》依據(jù)：Km=KmxdId1min/Idz=0.866*12023/16*100/1=6.5>22=Kmxd”d2n依據(jù)：Km=KmxdId2min/Idz=0.866*2968/5*100/1=5.14>1.54)、時(shí)限整定：64030.8S12、眾元洗煤廠6404〔CT變比：150/5〕1、速斷動(dòng)作電流dzj=kjx”d2max/1=1.2*1*12370/30=494.A〕 〔取50〕2、帶時(shí)限過(guò)電流淌作電流：g=160(A) 依據(jù)區(qū)變實(shí)際運(yùn)行負(fù)荷得出的值∴Idzj=KkKjxIgh/Khn1=1.2*1*160/1*30=6.4 〔A〕 〔6.3A〕3、靈敏系數(shù)校驗(yàn)(1、電流速斷保護(hù)靈敏度校驗(yàn)=Kmxd”d1min/Idz≥2 依據(jù)《繼電保護(hù)及二次回速查速算手冊(cè)》依據(jù)：Km=KmxdId1min/Idz=0.866*12023/50*30/1=6.9>22=Kmxd”d2n依據(jù)：Km=KmxdId2min/Idz=0.866*10606/5*30/1=61>1.54)、時(shí)限整定：64040.8S13、一采區(qū)Ⅱ路6406〔CT變比：1000/5〕1、速斷動(dòng)作電流dzj=kjx”d2max/1=1.2*1*4271/200=25.6A〕 〔取28〕2、帶時(shí)限過(guò)電流淌作電流：g=1724(A) 依據(jù)一采區(qū)600水平要上綜采工作面，金公司機(jī)械動(dòng)力部報(bào)來(lái)需增加負(fù)荷為：1724A.∴Idzj=KkKjxIgh/Khn1=1.2*1*1724/1*200=10.3〔A〕 〔取因要與一采變協(xié)作故取11.8A〕3、靈敏系數(shù)校驗(yàn)(1、電流速斷保護(hù)靈敏度校驗(yàn)=Kmxd”d1min/Idz≥2 依據(jù)《繼電保護(hù)及二次回速查速算手冊(cè)》依據(jù)：Km=KmxdId1min/Idz=0.866*12023/28*200/1=1.86<22=Kmxd”d2n依據(jù)：Km=KmxdId2min/Idz=0.866*4038/7*200/1=2.5>1.54)、時(shí)限整定：64060.8S14、石康鑄造6407〔CT變比：150/5〕1、速斷動(dòng)作電流dzj=kjx”d2max/1=1.2*1*7760/30=31A〕 〔取40〕2、帶時(shí)限過(guò)電流淌作電流：g=120(A) 依據(jù)區(qū)變實(shí)際運(yùn)行負(fù)荷得出的值∴Idzj=KkKjxIgh/Khn1=1.2*1*120/1*30=4.8〔A〕 〔15A〕3、靈敏系數(shù)校驗(yàn)(1、電流速斷保護(hù)靈敏度校驗(yàn)=Kmxd”d1min/Idz≥2 依據(jù)《繼電保護(hù)及二次回速查速算手冊(cè)》依據(jù)：Km=KmxdId1min/Idz=0.866*12023/40*30/1=8.6>22=Kmxd”d2n依據(jù)：Km=KmxdId2min/Idz=0.866*7023/15*30/1=13.5>1.54)、時(shí)限整定：64070.8