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生物化學新陳代謝篇OxidativePhosphorylationATP
synthaseProton-motive
force:
two
components可參考電能的計算Welectricity
=
V?q++++++++++++V+電勢(Volt)點電荷(Cullen)因為實際穿越的是質(zhì)子,而不是點電荷,所以這里能量的計算以1mol質(zhì)子跨膜作為標準。We
=
V?NA
?e質(zhì)子的電量1.6e-19Avogadro
常數(shù)6.02e23=
V?FFaraday
常數(shù)96485
C/mol0.14
Volt=
13.5
kJ/mol+
-+
-+
-+
-+
-化學能的計算++++++++++++ABGAGB10?7MGB
=
Go’
+
RT
ln[H+]BGA
=
Go’
+
RT
ln[H+]A?G
=
RT
ln[H+]B
/[H+]A=
2.303RT
log10[H+]B
/[H+]A在很多情況下,線粒體內(nèi)膜兩邊的PH值差大約為1.4(matrix
高
intermembrane
space
低)log10[H+]B
/[H+]A
=
1.4?G
=
8.3
kJ/mol總能量:We
+
?G
=
21.8
kJ/molATP
synthase
(complex
V)Ball
on
a
stickF0F1Some
stick
part
γ,
ε belong
to
F1
subunitcF0
subunit:
much
of
the
stick
part10—14
c
subunits
forming
a
ringThe
ring
constitutes
the
proton
channel.1
a
subunit
binds
to
the
outside
of
the
ringF1
subunit:γ,
ε
–
the
sticky
partα,
β,
α,
β,
α,
βδF0
–
F1
connectiontwo
b
subunitsMatrixIntermembrane
spaceBlue
part: rotor
(moving)Other
part: stator
(stationary)The
reactionIt
is
intuitive
that
proton-active
force
provides
the
energy.To
verify
thisThey
use
a
special
water,
H2
18O
for
testing.Theyaddthis
H218Ointo
ADP,
Pi,
and
ATP
synthase,in
the
absence
of
proton-active
forceThey
found
18O
in
PiThis
implies
the
following
reaction
has
occurred:Where
did
ATP
comefrom?This
means
the
reaction
proceeds
evenwithout
the
proton-motive
force.ATP was
synthesized
from
ADP and
Pi
,
by
ATP
synthaseIn
totalIn
the
early
1980’s,
Paul
Boyer
at
UCLA,
proposed
the
surprisingtheory
that,
in
the
catalytic
sites
of
F1,
ATPwas
in
chemicalequilibrium
with
its
reactants,
ADP
and
phosphate.
So
theformation
of
ATP
in
the
catalytic
sites
was
essentially
withoutenergetic
cost.Nobel
Prize
in
Chemistry
(1997)The
role
of
the
proton
gradient
is
not
to
form
ATPbut
to
release
it
from
the
synthaseThree
steps:ThreeAre
there
3
components
in
structure?α,
β,
α,
β,
α,
βThree
β
subunits:
catalyze
the
above
three
tasks.The
three
β
subunits
are
the
sameBut
the
three
tasks
are
different.How
could
the
same
β
perform
different
tasks?LooseTightOpenThree
α
subunits:
Primarily
for
holding.It
is
the
γ
subunit
that
breaks
the
symmetry:each
of
the
β
subunits
is
distinct
by
virtue
ofIts
interaction
with
a
different
face
of
γ鈍角平角銳角Loose
conformation: just
binds
ADP
and
PiTightconformation: binds
with
great
avidity,
so
much
so
thatADPand
Pi converts
into
ATPOpen
conformation: allows
ATP
to
bereleasedOne
120
rotation
of
γ
counterclockwiseBlue
subunit:L
T
O
Green
subunit:O
L
T
O
L
Yellow
subunit:T
O
L
T
O
L
T
L
T
O
The
binding-change
mechanismSubunit?Subunit
cA
proton
gets
into
the
cytoplasmic
half-channel
of
the
a
Subunit
aIt
cannot
escape
if
the
Subunit
a
does
not
interact
with
othersThe
interaction
from
Subunit
c
gives
a
chance
to
the
proton.H+1.
Subunit
c
has
a
negatively
charged
residue2.
The
residue
attracts
the
protonThe
attraction
neutralizes
the
negative
chargeThis
leads
to
the
rotation
of
c
subunits (will
be
explained).5.
It
is
the
rotation
of
the
c
subunits
that
takes
away
the
protonWhy
does
the
proton
leave
the
matrix
half
channel?Diffusion?No. One
proton
does
not
diffuse
intomany
protons.Because
of
the
aspartic
acid
residue?No.
The
attraction
would
keep
the
proton.Then
what’s
the
reason?The
half
channel
must
be
polarand
positively
charged!The
charge
must
be
sufficiently
largeTo e
chemical
and
electrical
potentialThis
however
brings
about
a
problem:How
did
the
proton
load
in
the
first
place?H+It
is
the
power
of
chemical
diffusionWhy
rotate?The
essence
is
why
subunit
c
would
like
toLeave
the
cytoplasmic
half
channel?To
understand
this,
onehas
to
understandwhy
subunit
c
stabilizes
in
the
channel
beforereceiving
H+Because
one
positive,
the
other
negative+++–Because
of
H+,
subunit
c es
neutralized,and es
hydrophobicSubunit
c
leaves
to
find
other
hydrophobe:Lipid
bilayer.物以類聚Which
direction
to
rotate?Seen
from
bottom
upThat
subunit
c is
now
hydrophobic, it
wants
to
leave
the
hydrophilic subunit
aIf
the
following
direction,then
it
will
still
be
in
subunit
a,still
hydrophilic.So
must
be
the
following
direction.CounterclockwiseThe
direction
is
caused
by
asymmetryIf
symmetric,
then
no
preferred
directionSummaryDoes
α3β3
rotate
with
the
γ
unit?No.
If
otherwise,
then
α3β3
are
relatively
static
with
γ,rotation
loses
its
meaning.How
to
prevent
the
rotation
of
α3β3?The
two
b
chains
andthe
δ
subunit
fix
it
firmlyThe
number
of
c
subunits
10
—
14 is
significant2.
One
360
degree
rotation
generates
3
ATPsTake
n
=
12
as
anexample1.
One
360
degree
rotation
passes
through
12
protons3.
So
the
generation
of
one
ATP
requires4
protons.Let’s
evaluate
how
many
protons
pass
through
ATP
synthase
everydayfor
a
regular
resting
man.Recall
that
a
regular
man
generate
ATP
at
an
amount
about
his
weight.Suppose
his
weight
is
85
kg.The
molecular
weight
of
ATP
(C10H16N5O13P3) is
about
507So
everyday
the
person
generate
85000/507
=
170
mol
ATPThis
requires
passing
through
170*4
=
680
mol
of
protonsThis
is
about
680*6.02x1023
=
4x1026
of
protons
p
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