2017年電大《高等數(shù)學(xué)基礎(chǔ)》必過考試小抄

小抄版高等數(shù)學(xué)基礎(chǔ)歸類復(fù)習(xí)考試小抄一、單項(xiàng)選擇題1-1 下列各函數(shù)對中，（ C ）中的兩個(gè)函數(shù)相等A. ， B. ，2)(xfxg(2)(xfxg)(C. ， D. ，3lnln1121-設(shè)函數(shù) 的定義域?yàn)?，則函數(shù) 的圖形關(guān)于（C ）對稱)(f),()(fA. 坐標(biāo)原點(diǎn) B. 軸 C. 軸 D. xyx設(shè)函數(shù) 的定義域?yàn)?，則函數(shù) 的圖形關(guān)于（D ）對稱x)fA. B. 軸 C. 軸 D. 坐標(biāo)原點(diǎn)y.函數(shù) 的圖形關(guān)于（ A ）對稱2ex(A) 坐標(biāo)原點(diǎn) (B) 軸 (C) 軸 (D) yxy1-下列函數(shù)中為奇函數(shù)是（ B ）A. B. C. D. )1ln(2xyxycos2xa)1ln(x下列函數(shù)中為奇函數(shù)是（A ）A. B. C. D. 3xe)1ln(yysi下列函數(shù)中為偶函數(shù)的是（ D ）A B C D xysin)1(x2xcos)1ln(2x2-1 下列極限存計(jì)算不正確的是（ D ）A. B. 2limx 0)1ln(im0xC. D. 0sns2-2 當(dāng) 時(shí)，變量（ C ）是無窮小量A. B. C. D. xix1x1in2)l(x當(dāng) 時(shí)，變量（ C ）是無窮小量A B C D 0si1e2x.當(dāng) 時(shí)，變量（D ）是無窮小量 A B C D xx)ln(下列變量中，是無窮小量的為（ B ）A B C D.1sin0xln101xe24x3-1 設(shè) 在點(diǎn) x=1 處可導(dǎo)，則 （ D ）)(xf hffh)1(2(lim0A. B. C. D. 1)1 )1(2f設(shè) 在 可導(dǎo)，則 （ D ）)(f0 xfxfh)(li00A B C D x)2 )(0xf設(shè) 在 可導(dǎo)，則 （ D ）)(f0 ffh)(li00A. B. C. D. )(f)x2 )(0f設(shè) ，則 （ A ） A B. C. D. xfe)(ff1(lim0 e2e143-2. 下列等式不成立的是（D ）A. B C. D.xxd)(cossinxdxd2)(lnxd下列等式中正確的是（B ）A. B. artn122)1(C. D.xx)l( xcotta4-1 函數(shù) 的單調(diào)增加區(qū)間是（ D ）4)(2xfA. B. C. D. ,),(),(函數(shù) 在區(qū)間 內(nèi)滿足（A ）5y)6(A. 先單調(diào)下降再單調(diào)上升 B. 單調(diào)下降 C. 先單調(diào)上升再單調(diào)下降 D. 單調(diào)上升.函數(shù) 在區(qū)間（5，5）內(nèi)滿足（ A ）62xA 先單調(diào)下降再單調(diào)上升 B 單調(diào)下降 C 先單調(diào)上升再單調(diào)下降 D 單調(diào)上升. 函數(shù) 在區(qū)間 內(nèi)滿足（D ）y),2(A. 先單調(diào)下降再單調(diào)上升 B. 單調(diào)下降 C. 先單調(diào)上升再單調(diào)下降 D. 單調(diào)上升5-1 若 的一個(gè)原函數(shù)是 ，則 （D ） A. B. C. D. )(xfx1)(f xln21x32.若 是 的一個(gè)原函數(shù)，則下列等式成立的是（ A ）。 )(FfA B )(aFxdxa )()(afbfdxba小抄版C D)(xFf )()(aFbdxfba5-2 若 ，則 （ B ）cosxfd)(A. B. C. D. incscsincxos下列等式成立的是（D ）A. B. )(d)(fxf )(xffC. D. d（ B ） A. B. C. D. xfx)(d32 )(3xf )(32xf)(1xf1（ D ） A B C D fx)(2 )(2xfxfd)(1)(2fxfd)(2-3 若 ，則 （ B ）cxF)(dA. B. C. D. )( cx)(2cxF)( cxF)(1補(bǔ)充： , 無窮積分收斂的是 xefxde d12函數(shù) 的圖形關(guān)于 y 軸 對稱。x10)(二、填空題函數(shù) 的定義域是 （3，+） )ln(392xf函數(shù) 的定義域是 （2，3） （3，4 xy4)ln( 函數(shù) 的定義域是 （5，2）xf1若函數(shù) ，則 1 0,2)(xf )(f2 若函數(shù) ，在 處連續(xù)，則 e ,)1)(kxf k.函數(shù) 在 處連續(xù)，則 2 02sin)(xkxf k函數(shù) 的間斷點(diǎn)是 x=0 ,sin1y函數(shù) 的間斷點(diǎn)是 x=3 。32x函數(shù) 的間斷點(diǎn)是 x=0 ey13-曲線 在 處的切線斜率是 1/2 )(f)2,1(曲線 在 處的切線斜率是 1/4 x曲線 在（0，2）處的切線斜率是 1 f.曲線 在 處的切線斜率是 3 )(3),(3-2 曲線 在 處的切線方程是 y = 1 切線斜率是 0 xfsin1曲線 y = sinx 在點(diǎn) (0,0)處的切線方程為 y = x 切線斜率是 1 4.函數(shù) 的單調(diào)減少區(qū)間是 （，0 ） )1l(2函數(shù) 的單調(diào)增加區(qū)間是 （0，+） exf.函數(shù) 的單調(diào)減少區(qū)間是 （，1 ） 2.函數(shù) 的單調(diào)增加區(qū)間是 （0，+） )(f函數(shù) 的單調(diào)減少區(qū)間是 （0，+） 2xy5-1 . deex2 xdsin22sitan x +C )(tan若 ，則 9 sin 3x cf3si)(f5-2 3 0 35d)21( 123dx0 exdx1ln下列積分計(jì)算正確的是（ B ）A B C D d)(1ex 0d)(1xex 0d12x小抄版0d|1x三、計(jì)算題（一）、計(jì)算極限（1 小題，11 分）（1 ）利用極限的四則運(yùn)算法則，主要是因式分解，消去零因子。（2 ）利用連續(xù)函數(shù)性質(zhì)： 有定義，則極限)(0xf )(lim00xffx類型 1： 利用重要極限 ， ， 計(jì)算1sinlx ksnkxtanli1-1 求 解： x5sin6lm0 56sil5si6l00xx1-2 求 解： 0tali3x x3tanlm0 31tanli101-3 求 解： =i.x類型 2： 因式分解并利用重要極限 ， 化簡計(jì)算。1)(slax1)sin(laa2-1 求 解： =)1sin(lm21xx )sin(lm21xx2)1(.i 2-2 解： 21slx 21)(.)1(sinlmsin(l21 xxx2-3 解： )3sin(4mx li3si)3si(43323 x類型 3：因式分解并消去零因子，再計(jì)算極限3-1 解： =4586li24x 4586li24xx )1(2lixx 32li4x3-2 31x3335m17x3-3 解 4lim2x 412lim)(2li4li2 xxxx其他： ， 0sin21lmsin1l020 xxxx 21sinlmsinl00xx， 546li2x 1li2x54362lix 3li2x（0807 考題）計(jì)算 解： =xsin8tal0xsin8tal048.sital0x（0801 考題 . ）計(jì)算 解 x2lim0 x2lim021li0x（0707 考題 .） = )1sin(31 4)3(1)sin(.l1 x（二） 求函數(shù)的導(dǎo)數(shù)和微分（1 小題，11 分）（1 ）利用導(dǎo)數(shù)的四則運(yùn)算法則 vu vu（2 ）利用導(dǎo)數(shù)基本公式和復(fù)合函數(shù)求導(dǎo)公式x)(ln 1)(aaxe ueu.xx2cs)(otanicssi xexex xxx sin).(cos)( cin2ocos isiin22 xxx eeeuos).(s)(sin.i 22 xxeeeusin).(sin)(co2i22類型 1： 加減法與乘法混合運(yùn)算的求導(dǎo)，先加減求導(dǎo)，后乘法求導(dǎo)；括號求導(dǎo)最后計(jì)算 。1-1 xy)3(解： 322xee1322xxe132xe1-2 xylncot解：小抄版xxxxxy ln2cs)(lnl)(cs)ln()(cot 2221-3 設(shè) ，求 exay解： xexxeyxx 1scta1)(tat)(l)t( 2類型 2： 加減法與復(fù)合函數(shù)混合運(yùn)算的求導(dǎo)，先加減求導(dǎo)，后復(fù)合求導(dǎo)2-1 ，求 解：lnsi2y o)(ln(si 222-2 ，求 ecoxy解： 222 csesi).(cos).(sin)(si)( xxexxx 2-3 ，求 ， 解：x5lnyy 5455lnl類型 3： 乘積與復(fù)合函數(shù)混合運(yùn)算的求導(dǎo)，先乘積求導(dǎo)，后復(fù)合求導(dǎo)，求 。 解：eyxcos2 xexex sico2)(cs)( 22其他： ，求 。xy解： 2).(c.)(ln)o() xyx2csinl2xx0807.設(shè) ，求 解：siey2sinin cos)()( xeyx0801.設(shè) ，求 解：2x 222)()( xxxee0707.設(shè) ，求 解：sin cos.ininsi 0701.設(shè) ，求 解：xyecoly xxy1.l（三）積分計(jì)算：（2 小題，共 22 分）湊微分類型 1： )1(d2xx計(jì)算 解：xcos2 cxd1sin)(coscos20707.計(jì)算 解： xd1sin2 cxx1os)(dsin1si20701 計(jì)算 解： e2 ed121xe湊微分類型 2： x.計(jì)算 解： xdcos cxdxxsin2cosdcos0807.計(jì)算 解：in oin2in0801.計(jì)算 解： xed cexdexex湊微分類型 3： ， dln1 )ln(1a計(jì)算 解：xdln cxdux|lll.計(jì)算 解： e12 e1e1 )ln2()dl(2x5)l(1ex5 定積分計(jì)算題，分部積分法類型 1： cxaxdaxaxdaxd aaa 12111 )(lnlnlnln計(jì)算 解： ， e1 24l241)ln(ln2lxd21 exxe 0)l(lne1 e小抄版計(jì)算 解： ， e12dlnx2a cxxdx 1ln)1(lnl2e2)ne1e1 計(jì)算 解： ，dxe1ln2a cxxdx 4ln2ll=de1n4)4l(ln21 exxde0807 el 9421)9ln32( nd3233e1 ex0707 ee12xllx 33類型 2 ceaxdaxa21)(xxede2101041042xx1)(1exxxdede210102 4130)4222exx（0801 考題） e(10x類型 3： caxadaxaxd sin1cocoscssin 2xx sin1in1ico20sinxd 02)sico(s20 x20cosxd 120)cosin(si20 xx cxdsin421coin20sxd 402)i1cos(s20 xx2 200 011coin|in|4d 四、應(yīng)用題（1 題，16 分）類型 1： 圓柱體上底的中心到下底的邊沿的距離為 l，問當(dāng)?shù)装霃脚c高分別為多少時(shí)，圓柱體的體積最大？解：如圖所示，圓柱體高 與底半徑 滿足 hr22rh圓柱體的體積公式為 lV)(2求導(dǎo)并令 0)3(2l得 ，并由此解出 lr6即當(dāng)?shù)装霃?，高 時(shí)，圓柱體的體積最大lr36h類型 2：已知體積或容積，求表面積最小時(shí)的尺寸。2-1（0801 考題） 某制罐廠要生產(chǎn)一種體積為 V 的有蓋圓柱形容器，問容器的底半徑與高各為多少時(shí)用料最??？解：設(shè)容器的底半徑為 ，高為 ，則其容積rh22.,.rhr表面積為 rS2， 由 得 ，此時(shí) 。24rV 0S32V34Vrh由實(shí)際問題可知，當(dāng)?shù)装霃?與高 時(shí)可使用料最省。3r一體積為 V 的圓柱體，問底半徑與高各為多少時(shí)表面積最??？ 解： 本題的解法和結(jié)果與 2-1 完全相同。生產(chǎn)一種體積為 V 的無蓋圓柱形容器，問容器的底半徑與高各為多少時(shí)用料最?。拷猓涸O(shè)容器的底半徑為 ，高為 ，則無蓋圓柱形容器表面積為 rh l小抄版，令 ， 得 rVrhS2202rVS，Vr,3由實(shí)際問題可知，當(dāng)?shù)装霃?與高 時(shí)可使用料最省。3rrh2-2 欲做一個(gè)底為正方形，容積為 32 立方米的長方體開口容器，怎樣做法用料最?。浚?707 考題）解： 設(shè)底邊的邊長為 ，高為 ，用材料為 ，由已知 ， ，xhy322Vhx2xh表面積 ，xVy422令 ，得 ， 此時(shí) =2042xV63 ,4x2由實(shí)際問題可知， 是函數(shù)的極小值點(diǎn)，所以當(dāng) ， 時(shí)用料最省。h欲做一個(gè)底為正方形，容積為 62.5 立方米的長方體開口容器，怎樣做法用料最??？解： 本題的解法與 2-2 同，只需把 V=62.5 代入即可。類型 3 求 求曲線 上的點(diǎn)，使其到點(diǎn) 的距離最短kxy2 )0,(aA曲線 上的點(diǎn)到點(diǎn) 的距離平方為,aaxL2)()(， 0 kx23-1 在拋物線 上求一點(diǎn)，使其與 軸上的點(diǎn) 的距離最短 xy42 )0,3(解：設(shè)所求點(diǎn) P（x，y），則滿足 ，點(diǎn) P 到點(diǎn) A 的距離之平方為y4)()3(22令 ，解得 是唯一駐點(diǎn)，易知 是函數(shù)的極小值點(diǎn)，0L1x1x當(dāng) 時(shí)， 或 ，所以滿足條件的有兩個(gè)點(diǎn)（1，2）和（1，2）13-2 求曲線 上的點(diǎn)，使其到點(diǎn) 的距離最短xy2 ),(A解：曲線 上的點(diǎn)到點(diǎn) A（2，0） 的距離之平方為x)()(令 ，得 ， 由此 ， L122xyy即曲線 上的點(diǎn)（1， ）和（1， ）到點(diǎn) A（2，0）的距離最短。xy208074 求曲線 上的點(diǎn)，使其到點(diǎn) A（0，2）的距離最短。解： 曲線 上的點(diǎn)到點(diǎn) A（0，2）的距離公式為 2xy222 )()(yyxd與 在同一點(diǎn)取到最大值，為計(jì)算方便求 的最大值點(diǎn)，2d3)(1y令 得 ，并由此解出 ，0)(223y6x即曲線 上的點(diǎn)（ ）和點(diǎn)（ ）到點(diǎn) A（0，2）的距離最短x,6,2ag an employment tribunal clai Emloyment tribunals sort out disagreements between employers and employees. You may need to make a claim to an employment tribunal if: you dont agree with the disciplinary action your employer has taken against you your employer dismisses you and you think that you have been dismissed unfairly. For more informu, take advice from one of the organisations listed under Fur ther help. Employment tribunals are less formal than some other courts, but it is still a legal process and you will need to give evidence under an oath or affirmation. Most people find making a claim to an employment tribunal challenging. If you are thinking about making a claim to an employment tribunal, you should get help straight away from one of the organisations listed under Further help. ation about dismissal and unfair dismissal, see Dismissal. You can make a claim to an employment tribunal, even if you havent appealed against the disciplinary action your employer has taken against you. However, if you win your case, the tribunal may reduce any compensation awarded to you as a result of your failure to appeal. Remember that in most cases you must make an application to an employment tribunal within three months of the date when the event you are complaining about happened. If your application is received after this time limit, the tribunal will not usually accept i. If you are worried about how the time limits apply to you If you are being represented by a solicitor at the tribunal, they may ask you to sign an agreement where you pay their fee out of your compensation if you win the case. This is known as a damages-based agreement. In England and Wales, your solicitor cant charge you more than 35% of your compensation if you win the case. You are clear about the terms of the agreement. It might be best to get advice from an experienced adviser, for example, at a Citizens Advice Bureau. To find your nearest CAB, including those that give advice by e-mail, click on nearest CAB. For more information about making a claim to an employment tribunal, see Employment tribunals. The (lack of) air up there Watch m Cay man Islands-based Webb, the head of Fifas anti-racism taskforce, is in London for the Football Associations 150th anniversary celebrations and will attend Citys Premier League match at Chelsea on Sunday. “I am going to be at the match tomorrow and I have asked to meet Ya ya Toure,“ he told BBC Sport. “For me its about how he felt and I would like to speak to him first to find out what his experience was.“ Uefa has opened disciplinary proceedings against CSKA for the “racist behaviour of their fans“ during Citys 2-1 win. Michel Platini, president of European footballs governing body, has also ordered an immediate investigation into the referees actions. CSKA said they were “surprised and disappointed“ by Toures complaint. In a statement the Russian side added: “We found no racist insults from fans of CSKA.“ Age has reached the end of the beginning of a word. May be guilty in his seems to passing a lot of different life became the appearance of the same day; May be back in the past, to oneself the paranoid weird belief disillusionment, these days, my mind has been very messy, in my mind constantly. Always feel oneself should go to do something, or write something. Twenty years of life trajectory deeply shallow, suddenly feel something, do it.一字開頭的年齡已經(jīng)到了尾聲。或許是愧疚于自己似乎把轉(zhuǎn)瞬即逝的很多個(gè)不同 的日子過成了同一天的樣子；或許是追溯過去，對自己那些近乎偏執(zhí)的怪異信念的醒 悟，這些天以來，思緒一直很凌亂，在腦海中不斷糾纏?？傆X得自己似乎應(yīng)該去做點(diǎn) 什么，或者寫點(diǎn)什么。二十年的人生軌跡深深淺淺，突然就感覺 到有些事情，非做不可了。The end of our life, and can meet many things really do? 而窮盡我們的一生，又能遇到多少事情是真正地非做不可？ During my childhood, think lucky money and new clothes are necessary for New Year, but as the advance of the age, will be more and more found that those things are optional; Junior high school, thought to have a crush on just means that the real growth, but over the past three years later, his writing of alumni in peace, suddenly found that isnt really grow up, it seems is not so important; Then in high school, think dont want to give vent to out your inner voice can be in the high school children of the feelings in a period, but was eventually infarction when graduation party in the throat, later again stood on the pitch he has sweat profusely, looked at his thrown a basketball hoops, suddenly found himself has already cant remember his appearance. Baumgartner the disappointing news: Mission aborted. r plays an important role in this mission. Starting at the ground, conditions have to be very calm - winds less than 2 mph, with no precipitation or humidity and limited cloud cover. The balloon, with capsule attached, will move through the lower level of the atmosphere (the troposphere) where our day-to-day weather lives. It will climb higher than the tip of Mount Everest (5.5 miles/8.85 kilometers), drifting even higher than the cruising altitude of commercial airliners (5.6 miles/9.17 kilometers) and into the stratosphere. As he crosses the boundary layer (called the tropopause),e can expect a 小抄版lot of turbulence. We often close ourselves off when traumatic events happen in our lives; instead of letting the world soften us, we let it drive us deeper into ourselves. We try to deflect the hurt and pain by pretending it doesnt exist, but although we can try this all we want, in the end, we