《C程序設計》課后習題全部答案

第一章習題編寫ー個C程序,輸入以下信息:Verygood!程序:#include<stdio.h>voidmain()〃信息輸出printW***************************************\n'').print吋Verygood!print吋Verygood!5”)；”***************************************、n'‘)■結果:■E:\C_CLASS\CLASS_1\C_1.5\Deb時'ressanykeytocontinue■E:\C_CLASS\CLASS_1\C_1.5\Deb時'ressanykeytocontinue編寫ー個c程序,輸入a,b,c3個值,輸出其中最大者。程序:#include<stdio.h>voidmain?！ㄖ骱瘮?shù){intmax(intx,inty,intz);inta,b,c,d；scanff%d,%d,%d”,&a,&b,&c);d=max(a,b,c);printffmax=%d\nH,d);}intmax(intx,inty,intz)〃三個數(shù)取最大{intm;iflfx>y&&x>z)m=x;iRy>x&&y>z)m=y;iRz>x&&z>y)m=z;retum(m);結果:"E:\C_CLASS\CLASS_1\C_1.6\Debug\c_1-6.exe'ト乙2nax=7tressanykeytocontinuel運行本章3個例題例ー結果:'E:\c_class\class_1\p_1\Debug\p_1.exe*[ThisisaCprogram.pressanykeytocontinue例二結果:"E:\c_class\class_1\p_2\Debug\p_2.exe"Isumis579Pressanykeytocontinue例三結果:"E:\c_class\class_1\p_3\Debug\p_3.exe'14.7Lax=7■Pressanykeytocontinue第二章習題2.8(1)輸出1900-2000年中的閏年程序:#include<stdio.h>voidmain(){inti;//inta;printf("1900-2000的閏年有An");fbr(i=1900;i<=2000;i++)〃依次判斷閏年if((((i%4)=0)&&((i%100)!=0))||(((i%100)=0)&&((i%400)=0)))a=i;printf(H%d\nM,i);'E:\C_CLASS\CLASS_2\C_2.8\Debug\c_2.8_1.exe'結果:'E:\C_CLASS\CLASS_2\C_2.8\Debug\c_2.8_1.exe'5ド900-2000的閏年有119041190811912119161192011924119281193211936119401194411948119521195611960119641196811972119761198011984119881199211996(2000[Pressanykeytocontinue(2)求aヽ?+bx+c=0的根。程序:#include<stdio.h>#include<stdio.h>#include<math.h>voidmain()floata,b,c,x,xl,x2;floatm;scanff'%f,%f,%F,&a,&b,&c);m=b*b-4*a*c;if(m>0)xl=(-b+sqrt((double)m))/(2*a);x2=(-b-sqrt((double)m))/(2*a);printグ％f,%f',xl,x2);ififm=0){x=-b/(2*a);printグ％F,x);)ififm<0){printグNone")；)}結果:ー個解:兩個解:沒有解:[1CiTiNonePressanykeytocontinue(3)輸入十個數(shù),輸出最大數(shù)程序:#include<stdio.h>voidmain()]intmax,i;intm[10];printク請輸入10個整數(shù):つ;〃輸入數(shù)組fbr(i=O;i<10;i++)

max=m[0];fbr(i=0;i<10;i++)|iRmax<m[i])(max=m[i];〃都和前一個最大的比較))printf("最大值是:%d\n",max);}結果:第三章習題3.10寫出運行結果8,10,8,11globalmembers^▼]#main

ョヨ▼手讎甚!卻四Sinclude<stdio.h>uoidnain()(inti,j,m,n;i=8;j=10；m=++i;n=j++；printr(''Xd,Zd,2d,2d\n",i,j;"E:\C_CLASS\CLASS_3\Debug\class_3.10.exe-p,11,9,10[Pressanykeytocontinue++i意思是先自加1,然后賦值計+意思是先賦值,然后自加1

第四章習題4.8設圓半徑r=1.5,圓柱髙h=3,求圓周長、圓面積、圓球體積、圓柱體積。程序://definepi3.14〃定義常量#include<stdio.h>//#include<math.h>voidmain(){floatr,h;floatc,s,sl,v,vl;printf("請輸入圓的半徑r,圓柱高h:\nn);scanf(M%f%f,,&r,&h);c=2*pi*r;s=pi*r*r;si=4*s;v=4*pi*r*r*r/3;vl=s*h;printfif”圓周長:c=%.2f\nH,c);printf(“圓面積:s=%,2f\nw,s);printff圓球面積:si=%.2f\n\sl);printグ圓球體積:v=%.2f\n",v);printf("圓柱體積:vl=%.2f\nM,vl);}結果:圓.?圓.?■x34^面:S圓圓圓圓跟■E:\C_CLASS\CLASS_4\CLASS_4.8\Debug\class_4.8.exe,輸入ー個華氏溫度,要求輸出攝氏溫度。程序:#include<stdio.h>voidmain(){floatc,F;printff請輸入ー個華氏溫度:\n)scanfC'%r,&F);c=5*(F-32)/9;printf("攝氏溫度為:%.2f\nM,c);結果:?E:\C_CLASS\CLASS_4\CLASS_49\Debug\dass_4S.exe.情輸入ー個華氏溫度:恨氏溫度為:-12.22Pressanykeytocontinue編程序,用getchar函數(shù)讀入兩個字符,然后分別用putchar和printf函數(shù)輸出。程序:#include<stdio.h>voidmain()(charcl,c2;printff請輸入兩個字符:'n)cl=getchar();c2=getchar();primff輸出結果:\nH);putchar(c1);putchar(へn');putchar(c2);putcharC'n*);printf(M%c\nw,cl);printf(M%c\nM,c2);結果:hb輸出結果:pressanykeytocontinue第五章習題輸入3個整數(shù),求最大程序:#include<stdio.h>voidmain()(inta,b,c,i;printf(”請輸入三個整數(shù):\n”)；scanf("%d,%d,%d,",&a,&b,&c);ifi(a>b)|i=a;a=b;b=i;}//endif(a>b)ifi(a>c)(i=a;a=c;c=i;}//endif(a>c)ifi(b>c){i=b;b=c;c=i;}//endif(b>c)printff最大數(shù)是:%d\nH,c);結果:"E:\C_CLASS\CLASS_5\CLASS34\Debug\class_5.4.exe"continue〇tyesk是an

奴s繭5,大es求函數(shù)的值(x x<1y=jlr-11ix<10(3ズー11 1在］。輸入x?輸出y。程序:#include<stdio.h>voidmain(){intx,y;primf("請輸入ー個整數(shù):也”);scanf(,*%dM,&x);if(x<l)y=x;ifi(x>=1&&x<10)y=2*x-1;if(x>=10)y=3*x-11;printf(Hy=%d\nn,y);}結果：CKl青銅CKl青銅人TW?E:\C.CLASS\CLASS.5\CLASS-5.5\Debug\class.5.5.exe"卜2IPressanykeytocontinueCl"E:\C_CLASS\CLASS_5\CLASS_5.5\Debug\class_5.5.exe?.?9Pressanykeytocontinue情輸入ー個整數(shù):レ=22[Pressanykeytocontinue要求輸出學生成績等級ABCDEo程序:#include<stdio.h>voidmain()intg,a;while(l)print%"請輸入一個成績:\n");scanf("%d",&g);a=g/10;switch(a)casecasecasecasecasecasecasecasecasecasecase10:printf("成績?yōu)锳\n");break;casecasecasecasecasecasecasecasecasecasecase9:printギ成績?yōu)锳\n");break;8:printff成績?yōu)锽\n");break;7:print"’成績?yōu)镃\n");break;6:printff成績?yōu)镈\n");break;5:printff’成績?yōu)镋\n");break;4:printff成績?yōu)镋\n");break;3:printf("成績?yōu)镋\n");break;2:printff成績?yōu)镋\n");break;1:printff’成績?yōu)镋\n");break;〇:printff成績?yōu)镋\n");break;default:printff,輸入成績有誤!\n");結果:

n□幀績?yōu)镋E青輸入一個成績:E0隨後人辻在『青輸入一個成績:|66幀績?yōu)镈樓輸入一個成績:F77幀績?yōu)镃儲輸入一個成績:S8他無力B儲輸入一個成績:,9政績?yōu)锳信輸ス一個成績:pl0E冃輸入一個成績:5.フ給ー個不多于5位的正整數(shù).求他是幾位數(shù).分別輸出每一位.逆序輸出各位數(shù)字程序:/*給ー個不多于5位的正整數(shù).求他是幾位數(shù).分別輸出每一位.逆序輸出各位數(shù)字*/#include<stdio.h>voidmain()(inti,num,g,s,b,q,w;printf("請輸入ー個不多于5位的正整數(shù):'n");scanfi["%d",&num);if(numif(num>9999)i=5;elseif(num>999)(i=4;)elseif(num>99)(i=3；)elseif(num>9)(i=2;)elseif(num>0)(i=1；)printf("這是ー個％d位數(shù)。\n",i);w=num/10000;q=(num-(10000*w))/1000;b=(num-(10000*w)-(1000*q))/100;s=(num-(10000*w)-(1000*q)-(100*b))/10;g=num-10000*w-1000*q-100*b-10*s;printf("這個％d位數(shù)的每一位是:'n",i);switch(i)(printf(,,%d\n",g);break;printf("%d,%d\nn,s,g);break;printf(,,%d,%d,%d\nu,b,s,g);break;printf(,,%d,%d,%d,%d\n,,,q,b,s,g);break;printfi(',%d,%d,%d,%d,%d\nH,w,q,b,s,g);break;}printf("這個％d位數(shù)的逆序數(shù)字是:\n”,i);switch(i){printf("%d\n",g);break;printfi("%d%d\n,,,g,s);break;printfC*%d%d%d\nM,g,s,b);break;printfi(',%d%d%d%d\n,,,g,s,b,q);break;printf(,,%d%d%d%d%d\nM,g,s,b,q,w);break;結果:"E:\C_CLASS\CLASS_5\CLASS_5.ADebug\class_57.exe"R青輸入ー個不多于5位的正整數(shù):囪位數(shù)的逆序數(shù)字是:[Pressanykeytocontinue5.8輸入4個整數(shù),要求由小到大的順序輸出。程序:#include<stdio.h>voidmain(){intij,temp;intm[4];printfC請輸入4個整數(shù):、ザ;fbr(i=0;i<=3;i++)scanf(M%d,,,&m[i]);for(j=0;j<=3;j++)fbr(i=0;i<=3-j;i++)l]<m[i]){temp=m[i+1];m[i+l]=m[i];m[i]=temp;for(i=0;i<=3;i-H-){printf(M%dM,m[i]);結果:

請輸入4個整數(shù):39622369Pressanykeytocontinue5.10有4個圓塔,輸入任意一點的坐標,求該點的髙度。程序:/?有4個圓塔,輸入任意一點的坐標,求該點的高度。*/#include<stdio.h>voidmain()inth=10;floatx1=2,y1=2,x2=-2,y2=2,x3=-2,y3=-2,x4=-2,y4=-2；floatx,y,dl,d2,d3,d4;printグ輸入ー個坐標(x,y):");〃求該點到各中心點的距離scanfC%f,%P,&x,&y);〃求該點到各中心點的距離dl=(x-xl)*(x?xl)+(y-yl)*(y-yl);d2=(x-x2)*(x-x2)+(y+y2)*(y+y2);d3=(x+x3)*(x+x3)+(y?y3)*(y-y3);d4=(x+x4)*(x-x4)*(y+y4)*(y+y4);iRdl>1&&d2>1&&d3>1&&d4>1)(h=0; 〃判斷該點是否在塔外printf("該點的高度為％d\n",h);結果:^^一主坐懷^^一主坐懷核點的咼度為[Pressanykeytocontinue第六章習題求兩個數(shù)的最大公約數(shù)、最小公倍數(shù)程序:#include<stdio.h>voidmain()inta,b,i,n,mg,mb;printf("請輸入兩個正整數(shù):\nH);scanff%d,%d”,&a,&b);if(a>b)n=b;elsen=a;fbr(i=n;i>0;i-){if((a%i==0)&&(b%i=0))|mg=i;break;})printff最大公約數(shù)為:%d\nn,mg);mb=a*b/mg;printff最大公倍數(shù)為:%d\nn,mb);｝結果:"E:\C_CLASS\CLASS_6\CLASS_6.1\Debug\class_6.1.exe"情輸入兩個正整數(shù):124.36廬ボ金包鑿カ:12區(qū)大公％數(shù)為:72Pressanykeytocontinue輸入一行字符,統(tǒng)計字符個數(shù)程序:#include<stdio.h>voidmain(){chars;inti;inta=b=c=d=0;printグ請輸入一行字符:'n");while((s=getchar())!=へn')if((s>=n&&s<=,z,)||(c>=,A,&&c<=(Z*))a-H-；elseif(s>='O'&&s<='9')(b++;)elseif(s='')(c++;)else(d++;)printf("字母數(shù)為:%d\n",a);printf("數(shù)字數(shù)為:%d\n",b);printf("空格數(shù)為:%d\n",c);printf("其他字符數(shù)為:%d\n",d);)結果:"E:\C_CLASS\CLASS_6\CSSS_6.2\Debug\class_62.exe.-3為為春-3為為春an關12數(shù)數(shù)釁于S琳C母字負es滿lab字夢工其Iprcontmue求算式的值程序:#include<stdio.h>voidmain()inta,n,sn;inti,b,temp;printf("請輸入兩個正整數(shù)(a,n):\n");scanff"%d,%d",&a,&n);sn=a;b=a;

fbr(i=l;i<n;i-H-){temp=b*10;b=temp+a;〃后一個數(shù)sn=sn+b;}printf(Hsn的結果為:%d\n*',sn);}EK結果:EK"E:\c_class\class_6\class_6.3\Debug\class_6.3.exe"情輸入兩個正整數(shù)3n〉:M的結果為:24690DPressanykeytocontinue求!!+2!+〇〇〇〇〇〇+20!程序:#include<stdio.h>voidmain(){inti,n;longsum=O,temp;printff請輸入ー個正整數(shù)(n)：\nM);scanf(M%dM,&n);temp=1;fbr(i=l;i<=n;i++){temp=i*temp;sum=sum+temp;}printff結果為:%ld\nn,sum);結果:

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請20人為s

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請20結pri268040729anykeytocontinue求算式的E盟A+E氏1バ+E溝,程序:#include<stdio.h>voidmain()(inti;intsl,s2;floats,s3;=s2=1;=s3=1;fbr(i=2;i<=100;i++)(=si+i;)fbr(i=2;i<=50;i++)(=s2+i*i;)fbr(i=2;i<=10;i++){=s3+1/(float)i;)s=(float)si+(float)s2+s3;printf("算式的值為:%f\n",s);結果:0I"E:\c_class\class_6\class_6.5\Debug\class_6.5.exe"0I昌式的值為:47977.928968pressanykeytocontinue6?6輸出所有的水仙花數(shù)程序:/?輸出所有的水仙花數(shù)?/#include<stdio.h>voidmain()inta,b,c;inti;primf("水仙花數(shù)有:、ガ);fbr(i=100;iv=999;iH)a=i”。〇;〃百位b=(i?(a*100))ハ。;〃十位c=i?(a*100)?(b*1。);〃個位if(i=a*a*a+b*b*b+c*c*c)printfC%d\n”,i);}｝結果:"E:\C_CLASS\CLASS_6\CLASS_6.6\Debug\class_6.6.exe"妙仙花數(shù)有:.53B70B71ke?[Pressanykeytocontinue6.フ找出1000以內的所有完數(shù)程序:/?找出1000以內的所有完數(shù)?/#include<stdio.h>voidmain(){intij;intnum;fbr(i=l;i<=1000;i++)num=0;fbr(j=l;j<=i/2;j++)if(i%j=O){num=num+j;})if(i==num)(printf("\n%4d\n",i);fbr(j=l；j<=i/2;j++)(if(i%j=O){printf("%4d"j);}}))}結果:有一數(shù)列2/1,3/2,5/3,8/5,13/8,21/13…“求前20項之和程序:/?求數(shù)列2ハ,3/2,5/3,8/5,13/8,21ハ3…..求前20項之和?/#include<stdio.h>voidmain(){inti;floatx,y;floattempi,temp2;floatsum=0;x=1;y=2；for(i=l；i<=20;i++){tempi=y/x;temp2=x;x=y;y=y+temp2;sum=sum+tempi;)printff%f\n”,sum);)結果:"E:\C_CLASS\CLASS_6\CLASS_6.8\Debug\class_6.8.exe"R2.660263[Pressanリkeytocontinueー個球從100米髙落下,每次跳回原來的一半,求第10次落地經(jīng)過多少米,第10次彈多髙程序:/?ー個球從100米髙落下,每次跳回原來的一半,求第10次落地經(jīng)過多少米,第10次彈多高?*/#include<stdio.h>voidmain(){floath=100;floats=0;inti;for(i=l;i<10;i++)(s=s+h;h=h/2;printf（"第十次反彈的高度為:%f\nH,h）;printf（"第十次落地經(jīng)過高度為:%f\n”,s）;結果:"E:\c_class\class_6\class_6.9\Debug\class_6.9.exe"區(qū)洛

次次++的咼度為:0區(qū)洛

次次++的咼度為:0經(jīng)対高度為:keytocont.195313199.609375inue猴子吃桃問題第一天吃了一半加一個,第二天又吃了剩下的一半加一個,以后每天都是前一天的一半加一個,第十天只剩下1個,問第一天摘了幾個桃子。程序:/?猴子吃桃問題。第一天吃了一半加一個,第二天又吃了剩下的一半加一個,以后每天都是前一天的一半加一個,第十天只剩下1個,問第一天摘了幾個桃子。*/#include<stdio.h>voidmain()(inti;intnum;num=0;fbr(i=1;i<=10;i++)|num=2*(num+1);printff%d\n”,num);｝結果:"E:\c_class\class_6\class_6.10\Debug\class_6.10.exe"E046(Pressanykeytocontinue.用迭代法求x=、,百程序:/?用迭代法求X=Va*/#include<stdio.h>#include<math.h>voidmain()inti;floatxnl,xn;floatnum,temp;printf("請輸入ー個正數(shù):M);scanfi(”％5F,&num);xn=10;while(fabs(xn-temp)>0.000001){xnl=0.5*(xn+(num/xn));temp=xn;xn=xnl;)printf("%5f\n",xnl);}結果:'E:\C_CLASS\CLASS_6\CLASS_6.11\Debug\class_6.11.exe園輸入ー不正數(shù);64R.000000[Pressanykeytocontinue用迭代法求方程1.5附近的根2バ_4バ+3ズーG程序:/?用迭代法求方程的1.5附近的根2xA3-4xM+3x-6=0*/#include<stdio.h>voidmain()(doublex,y;x=1.5;do{y=2*x*x*x-4*x*x+3*x=x-y/(6*x*x-8*x+3);}while(y!=0);printffx=%.3f\n”,x);結果:■E:\C_CLASS\CLASS_6\CLASS_6.12\Debug\class_6.12.exe'lx=2.000[Pressanykeytocontinue用二分法求(?10,10)之間的根2s.ZouX—4-X+iiX—0程序:/?用二分法求在(?10/0)之間的根2x八3?￡4x3A2+3x-6=0*/#include<stdio.h>voidmain(){doublexl,x2,yl,y2;xl=-10;x2=10;yl=2*xl*xl*xl-4*xl*xl+3*xl-6;xl=xl-yl/(6*xl*xl-8*xl+3);while(yl!=0);y2=2*x2*x2*x2-4*x2*x2+3*x2-6;x2=x2-y2/(6*x2*x2-8*x2+3);while(y2!=0);printf(Mxl=%.3f；x2=%.3f\n,,,xl,x2);}結果:"E:\C.CLASS\CLASS_6\CLASS.6.13\Debug\class_6.13.exe"pel=2.000，x2=2.000Pressanykeytocontinue輸出圖案程序:/?圖案輸出?/#include<stdio.h>

intij,k;fbr(i=0;i<=3;i++){ford=O；j<=(2-i);j++)(printf("M);}fbr(k=O;k<=2*i;k-H-)(printグ?”)；}printfCW");fbr(i=O;i<=2;i++)for。=0;j<=句++)fbr(k=0;k<=fbr(k=0;k<=4-(2*i);k++)printffW");第七章習題用篩選法求100之內的素數(shù)程序:/?用篩選法求100之內的素數(shù)?/#include<stdio.h>voidmain(){intnum[100];intij;for(i=3;i<=100;i++)(num[i]=i;for(j=2;j<=i-l;j++){ifi(i%j=0){break;))iRi=j)printf("%3d",i);)printf("\n");)結果:■' *E:\c_class\class_7\dass_7.1\Debug\class_7.1.exe"357111317192329313741434753596167717379838997Pykeytocontinue7.2用選擇法對10個整數(shù)排序/?用選擇法對10個整數(shù)排序?/#include<stdio.h>/?用選擇法對10個整數(shù)排序?/#include<stdio.h>voidmain()(intnum[10];intij;inttmp;printf(”請輸入10個整數(shù):\nH);fbr(i=O；i<10；i++)scanf(H%dH,&num[i]);for(j=O;j<10J-H-){fbr(i=0;i<10-j;i++){if(num[i]>num[i+l]){tmp=num[i];num[i]=num[i+l];num[i+l]=tmp;fbr(i=O;i<10;i++)(printf("%4d",num[i]);}printf("\n");)結果:"E:\C_CLASS\CLASS_ACLASS_7.2\Debug\class_72.exe"情輸入:10個整數(shù):し0481265-76100-45123-76-45 0 1 4 81265100123[Pressanykeytocontinue7.3求一個3*3矩陣對角線元素之和程序:/*求一個3*3矩陣對角線元素之和?/#include<stdio.h>voidmain(){inti;intsl,s2,num;inta[3][3]={{l,2,3},{4,5,6},{7,8,9}};sl=a[0][0]+a[l][l]+a[2][2];s2=a[0][2]+a[l][l]+a[2][0];num=si+s2;printfC%d\n”,num);結果:"E:\C_CLASS\CLASS_7\CLASS^73\Debug\classs.73.exeBPressanykeytocontinue7.4已有一個排好的數(shù)組,輸入ー個數(shù)后,按原來規(guī)律將他插入數(shù)組中程序:/?已有一個排好的數(shù)組,輸入ー個數(shù)后,按原來規(guī)律將他插入數(shù)組中?/#include<stdio.h>voidmain()(inta[10]={1,7,8,17,23,24,59,62,101};intij,t;printf("請輸入一個數(shù)字:\n");scanf("%d",&a[9]);fbr(i=9;i>0;i-){if(a[i]<a[i-l]){t=a[i-l];a[i-l]=a[i];a[i]=t;)}printf("排序結果是:'n");fbr(i=0;i<10;i++){printfK"%5d",a[i]);)printf("\n");結果:

n卜20岬序結果是:'E:\C_CLASS\CLASS_ACLASS_7.4\Debug\class_7.4.exe"-20 1 ? 8 17 23 24 59 62101'E:\C_CLASS\CLASS_ACLASS_7.4\Debug\class_7.4.exe"Pressanykeytocontinue5將一個數(shù)組中的值按照逆序重新存放程序:/?將一個數(shù)組中的值按照逆序重新存放?/#include<stdio.h>voidmain()(inti;intb[5];primf(”請輸入5個數(shù)字:\nM);fbr(i=0；i<5;i++){scanf("％d”,&b[i]);primff輸出結果為:\nH);fbr(i=4;i>-1;i—)(printf("%4d",b[i]);}printf("\n");)結果:■E:\C_CLASS\CLASS_7\CLASS_7.5\Debug\class_7.4.exe,,情輸入5個數(shù)字:№6542輸出結果為:2 45 6 8Pressanykeytocontinue7.6輸出楊輝三角（輸出10行）程序:/?輸出楊輝三角（輸出10行）*/#include<stdio.h>intm,n,k;intb[10][10];fbr(m=0;m<10;m++)fbr(m=1;m<10;m-H-)fbr(n=1;n<m;n++)b[m][n]=b[m-l][n-l]+b[m-l][n];fbr(m=0;m<10;m++)(fbr(n=0;n<=m;n++)(printf("%-4d",b[tn][n]);)printf("\n");))結果:?E:\C_CLASS\CLASS_ACLASS_7.6\Debug\class^7.6.exew1112113311464115101051161520156111721353521718285670562881119368412612684369iPressanykeytocontinue17.7輸出n階魔方陣程序:/?輸出n階魔方陣1、將1放在第一行中間一列2、從2開始到n*n止各數(shù)依次按下列規(guī)則存放:每ー個數(shù)存放的行比前ー個數(shù)的行數(shù)減1,列數(shù)加1。3、如果上一個數(shù)行數(shù)為1,則下ー個數(shù)行數(shù)為n(最下一行)4、當上一個數(shù)列數(shù)為n,下ー個數(shù)的列數(shù)應為15,如果按上面規(guī)則確定的位置上已經(jīng)有數(shù),或上一個數(shù)是1行n歹リ,則把下ー個數(shù)放在上ー個數(shù)的下面。*/#defineN5/*N為奇數(shù)?/#include<stdio.h>voidmain(){intij,n;intq[N][N];fbr(i=0;i<N;i++)for(j=0;j<N;j++){q[i]U]=O；)for(i=0j=N/2,n=1;n<=N*N;n++)(if(!q[(i+N-l)%N][(j+1)%N]){i=(i+N?1)%N;j=G+D%N;else〃將數(shù)放到前ー個數(shù)的下面i=(i+1)%N;q[i皿=n；for(i=0;i<N;i++)for(j=0;j<N;j++)(if(j%N=0)(printf(H\n");}printfC%3d",q[i]U])；printf(,,\nH);}結果:8找出ー個二維數(shù)組中的鞍點程序:/?找出ー個二維數(shù)組中的鞍點?/#include<stdio.h>voidmain()intarray[4][4]={{11,1,23,45},{40,56,98,91),{23,21,12,40},{45,67,23,90}};intnumber=0;intsign,ij,m,n;printff數(shù)組是:\n")；fbr(i=0;i<=3;i++)|for(j=0;j<=3;j++)printfCH%5dn,array[i][j]);printff\n")；)printff\n")；fbr(i=0;i<=3;i++)(m=i;n=0;sign=1;fbr(j=0;j<=3y-H-){if(array[m][n]<array.皿)(n=j；for(j=0;j<=3;j++)if(array[m][n]>array[j][n])sign=0;if(sign=l){printグ鞍點是%d\n",array[m][n]);number++；if(number==0)printf("沒有鞍點曲")；)結果:"E:\C_CLASS\CLASS_ACLASS_7.8\Debug\class,7.8.exe-TOC\o"1-5"\h\z11 1 23 4540 56 98 9123 21 12 4045 67 23 90鞍點是40Pressanykeytocontinue7.9有15個數(shù)按由大到小的順序存放到ー個數(shù)組里,輸入一個數(shù)要求用折半査找法找出該數(shù)是數(shù)組中第幾個元素的值程序:/?有15個數(shù)按由大到小的順序存放到ー個數(shù)組里,輸入ー個數(shù)要求用折半查找法找出該數(shù)是數(shù)組中第幾個元素的值?/#include<stdio.h>#include<math.h>main()(intij,m;inta[15]={1,4,9,13,21,34,55,89,144,233,377,570,671,703,812};printf("這個數(shù)列是:\n");fbr(j=0;j<15;j++)printf("%4d",a[j]);printf("\n");printf("請輸入ー個數(shù)字(m):\n");scanf("%d",&m);i=7；while(fabs(i-7)<8){if(m<a[7])(if(a[i]-m=0){printff這個數(shù)是在第％d位。\n",i+1);break;)i-；)elseif(m>a[7]){ifi(a[i]-m=0)(/r