高一數(shù)學(xué)函數(shù)公式總結(jié)

第4頁(yè)高一數(shù)學(xué)函數(shù)公式總結(jié)：期中考試已經(jīng)圓滿結(jié)束,在期中考試后或多或少我們都會(huì)找到自己的復(fù)習(xí)不到位的地方,小編為大家分享高一數(shù)學(xué)函數(shù)公式,希望能幫助大家復(fù)習(xí)知識(shí)!兩角和與差的三角函數(shù)cos(+)=coscos-sinsincos(-)=coscos+sinsinsin()=sincoscossintan(+)=(tan+tan)/(1-tantan)tan(-)=(tan-tan)/(1+tantan)和差化積公式sin+sin=2sin[(+)/2]cos[(-)/2]sin-sin=2cos[(+)/2]sin[(-)/2]cos+cos=2cos[(+)/2]cos[(-)/2]cos-cos=-2sin[(+)/2]sin[(-)/2]積化和差公式sincos=(1/2)[sin(+)+sin(-)]cossin=(1/2)[sin(+)-sin(-)]coscos=(1/2)[cos(+)+cos(-)]sinsin=-(1/2)[cos(+)-cos(-)]倍角公式sin(2)=2sincos=2/(tan+cot)cos(2)=(cos)^2-(sin)^2=2(cos)^2-1=1-2(sin)^2tan(2)=2tan/(1-tan^2)cot(2)=(cot^2-1)/(2cot)sec(2)=sec^2/(1-tan^2)csc(2)=1/2*seccsc三倍角公式sin(3)=3sin-4sin^3=4sinsin(60+)sin(60-)cos(3)=4cos^3-3cos=4coscos(60+)cos(60-)tan(3)=(3tan-tan^3)/(1-3tan^2)=tantan(/3+)tan(/3-)cot(3)=(cot^3-3cot)/(3cot^2-1)n倍角公式sin(n)=ncos^(n-1)sin-C(n,3)cos^(n-3)sin^3+C(n,5)cos^(n-5)sin^5-cos(n)=cos^n-C(n,2)cos^(n-2)sin^2+C(n,4)cos^(n-4)sin^4-半角公式sin(/2)=((1-cos)/2)cos(/2)=((1+cos)/2)tan(/2)=((1-cos)/(1+cos))=sin/(1+cos)=(1-cos)/sincot(/2)=((1+cos)/(1-cos))=(1+cos)/sin=sin/(1-cos)sec(/2)=((2sec/(sec+1))csc(/2)=((2sec/(sec-1))輔助角公式Asin+Bcos=(A^2+B^2)sin(+arctan(B/A))Asin+Bcos=(A^2+B^2)cos(-arctan(A/B))萬(wàn)能公式sin(a)=(2tan(a/2))/(1+tan^2(a/2))cos(a)=(1-tan^2(a/2))/(1+tan^2(a/2))tan(a)=(2tan(a/2))/(1-tan^2(a/2))降冪公式sin^2=(1-cos(2))/2=versin(2)/2cos^2=(1+cos(2))/2=covers(2)/2tan^2=(1-cos(2))/(1+cos(2))三角和的三角函數(shù)sin(++)=sincoscos+cossincos+coscossin-sinsinsincos(++)=coscoscos-cossinsin-sincossin-sinsincostan(++)=(tan+tan+tan-tantantan)/(1-tantan-tantan-tantan)其它公式1+sin(a)=(sin(a/2)+cos(a/2))^21-sin(a)=(sin(a/2)-cos(a/2))^2csc(a)=1/sin(a)sec(a)=1/cos(a)cos30=sin60sin30=cos60推導(dǎo)公式tan+cot=2/sin2tan-cot=-2cot21+cos2=2cos^21-