2022年c語言入門經(jīng)典必背程序

c語言入門典型必背個(gè)程序c語言入門典型必背18個(gè)程序1、/*輸出9*9口訣。共9行9列,i控制行,j控制列。*/#include"stdio.h"main(){inti,j,result;for(i=1;i<10;i++){for(j=1;j<10;j++){result=i*j;printf("%d*%d=%-3d",i,j,result);/*-3d表達(dá)左對齊,占3位*/}printf("\n");/*每一行后換行*/}}2、/*古典問題:有一對兔子,從出生后第3個(gè)月起每月都生一對兔子,小兔子長到第三個(gè)月后每月又生一對兔子,如果兔子都不死,問每月兔子總數(shù)為多少?兔子規(guī)律為數(shù)列1,1,2,3,5,8,13,21....*/main(){longf1,f2;inti;f1=f2=1;for(i=1;i<=20;i++){printf("%12ld%12ld",f1,f2);if(i%2==0)printf("\n");/*控制輸出,每行四個(gè)*/f1=f1+f2;/*前兩個(gè)月加起來賦值給第三個(gè)月*/f2=f1+f2;/*前兩個(gè)月加起來賦值給第三個(gè)月*/}}3、/*判斷101-200之間有多少個(gè)素?cái)?shù),并輸出所有素?cái)?shù)及素?cái)?shù)個(gè)數(shù)。程序分析:判斷素?cái)?shù)辦法:用一種數(shù)分別去除2到sqrt(這個(gè)數(shù)),如果能被整除,則表白此數(shù)不是素?cái)?shù),反之是素?cái)?shù)。*/#include"math.h"main(){intm,i,k,h=0,leap=1;printf("\n");for(m=101;m<=200;m++){k=sqrt(m+1);for(i=2;i<=k;i++)if(m%i==0){leap=0;break;}if(leap)/*內(nèi)循環(huán)結(jié)束后,leap依然為1,則m是素?cái)?shù)*/{printf("%-4d",m);h++;if(h%10==0)printf("\n");}leap=1;}printf("\nThetotalis%d",h);}4、/*一種數(shù)如果正好等于它因子之和,這個(gè)數(shù)就稱為“完數(shù)”。例如6=1＋2＋3.編程找出1000以內(nèi)所有完數(shù)。*/main(){staticintk[10];inti,j,n,s;for(j=2;j<1000;j++){n=-1;s=j;for(i=1;i<j;i++){if((j%i)==0){n++;s=s-i;k[n]=i;}}if(s==0){printf("%disawanshu:",j);for(i=0;i<n;i++)printf("%d,",k[i]);printf("%d\n",k[n]);}}}5、/*下面程序功能是將一種4×4數(shù)組進(jìn)行逆時(shí)針旋轉(zhuǎn)90度后輸出,規(guī)定原始數(shù)組數(shù)據(jù)隨機(jī)輸入,新數(shù)組以4行4列方式輸出,請?jiān)诳瞻滋幫晟瞥绦颉?/main(){inta[4][4],b[4][4],i,j;/*a存儲(chǔ)原始數(shù)組數(shù)據(jù),b存儲(chǔ)旋轉(zhuǎn)后數(shù)組數(shù)據(jù)*/printf("input16numbers:");/*輸入一組數(shù)據(jù)存儲(chǔ)到數(shù)組a中,然后旋轉(zhuǎn)存儲(chǔ)到b數(shù)組中*/for(i=0;i<4;i++)for(j=0;j<4;j++){scanf("%d",&a[i][j]);b[3-j][i]=a[i][j];}printf("arrayb:\n");for(i=0;i<4;i++){for(j=0;j<4;j++)printf("%6d",b[i][j]);printf("\n");}}6、/*編程打印直角楊輝三角形*/main(){inti,j,a[6][6];for(i=0;i<=5;i++){a[i][i]=1;a[i][0]=1;}for(i=2;i<=5;i++)for(j=1;j<=i-1;j++)a[i][j]=a[i-1][j]+a[i-1][j-1];for(i=0;i<=5;i++){for(j=0;j<=i;j++)printf("%4d",a[i][j]);printf("\n");}}7、/*通過鍵盤輸入3名學(xué)生4門課程成績,分別求每個(gè)學(xué)生平均成績和每門課程平均成績。規(guī)定所有成績均放入一種4行5列數(shù)組中,輸入時(shí)同一人數(shù)據(jù)間用空格,不同人用回車其中最后一列和最后一行分別放每個(gè)學(xué)生平均成績、每門課程平均成績及班級(jí)總平均分。*/#include<stdio.h>#include<stdlib.h>main(){floata[4][5],sum1,sum2;inti,j;for(i=0;i<3;i++)for(j=0;j<4;j++)scanf("%f",&a[i][j]);for(i=0;i<3;i++){sum1=0;for(j=0;j<4;j++)sum1+=a[i][j];a[i][4]=sum1/4;}for(j=0;j<5;j++){sum2=0;for(i=0;i<3;i++)sum2+=a[i][j];a[3][j]=sum2/3;}for(i=0;i<4;i++){for(j=0;j<5;j++)printf("%6.2f",a[i][j]);printf("\n");}}8、/*完善程序,實(shí)現(xiàn)將輸入字符串反序輸出,如輸入windows輸出swodniw。*/#include<string.h>main(){charc[200],c1;inti,j,k;printf("Enterastring:");scanf("%s",c);k=strlen(c);for(i=0,j=k-1;i<k/2;i++,j--){c1=c[i];c[i]=c[j];c[j]=c1;}printf("%s\n",c);}指針法:voidinvert(char*s){inti,j,k;chart;k=strlen(s);for(i=0,j=k-1;i<k/2;i++,j--){t=*(s+i);*(s+i)=*(s+j);*(s+j)=t;}}main(){FILE*fp;charstr[200],*p,i,j;if((fp=fopen("p9_2.out","w"))==NULL){printf("cannotopenthefile\n");exit(0);}printf("inputstr:\n");gets(str);printf(“\n%s”,str);fprintf(fp,“%s”,str);invert(str);printf(“\n%s”,str);fprintf(fp,“\n%s”,str);fclose(fp);}9、/*下面程序功能是從字符數(shù)組s中刪除存儲(chǔ)在c中字符。*/#include<stdio.h>main(){chars[80],c;intj,k;printf("\nEnterastring:");gets(s);printf("\nEnteracharacter:");c=getchar();for(j=k=0;s[j]!='\0';j++)if(s[j]!=c)s[k++]=s[j];s[k]='\0';printf("\n%s",s);}10、/*編寫一種voidsort(int*x,intn)實(shí)現(xiàn)將x數(shù)組中n個(gè)數(shù)據(jù)從大到小排序。n及數(shù)組元素在主函數(shù)中輸入。將成果顯示在屏幕上并輸出到文獻(xiàn)p9_1.out中*/#include<stdio.h>voidsort(int*x,intn){inti,j,k,t;for(i=0;i<n-1;i++){k=i;for(j=i+1;j<n;j++)if(x[j]>x[k])k=j;if(k!=i){t=x[i];x[i]=x[k];x[k]=t;}}}voidmain(){FILE*fp;int*p,i,a[10];fp=fopen("p9_1.out","w");p=a;printf("Input10numbers:");for(i=0;i<10;i++)scanf("%d",p++);p=a;sort(p,10);for(;p<a+10;p++){printf("%d",*p);fprintf(fp,"%d",*p);}system("pause");fclose(fp);}11、已知數(shù)組a中元素已按由小到大順序排列,如下程序功能是將輸入一種數(shù)插入數(shù)組a中,插入后,數(shù)組a中元素仍然由小到大順序排列*/main(){inta[10]={0,12,17,20,25,28,30};/*a[0]為工作單元,從a[1]開始存儲(chǔ)數(shù)據(jù)*/intx,i,j=6;/*j為元素個(gè)數(shù)*/printf("Enteranumber:");scanf("%d",&x);a[0]=x;i=j;/*從最后一種單元開始*/while(a[i]>x){a[i+1]=a[i];i--;}/*將比x大數(shù)往后移動(dòng)一種位置*/a[++i]=x;j++;/*插入x后元素總個(gè)數(shù)增長*/for(i=1;i<=j;i++)printf("%8d",a[i]);printf("\n");}12、/*編寫函數(shù)replace(char*s,charc1,charc2)實(shí)現(xiàn)將s所指向字符串中所有字符c1用c2替代,字符串、字符c1和c2均在主函數(shù)中輸入,將原始字符串和替代后字符串顯示在屏幕上,并輸出到文獻(xiàn)p10_2.out中*/#include<stdio.h>replace(char*s,charc1,charc2){while(*s!='\0'){if(*s==c1)*s=c2;s++;}}main(){FILE*fp;charstr[100],a,b;if((fp=fopen("p10_2.out","w"))==NULL){printf("cannotopenthefile\n");exit(0);}printf("Enterastring:\n");gets(str);printf("Entera&&b:\n");scanf("%c,%c",&a,&b);printf("%s\n",str);fprintf(fp,"%s\n",str);replace(str,a,b);printf("Thenewstringis----%s\n",str);fprintf(fp,"Thenewstringis----%s\n",str);fclose(fp);}13、/*在一種字串s1中查找一子串s2,若存在則返回子串在主串中起始位置,不存在則返回-1。*/main(){chars1[6]="thisis";chars2[5]="is";printf("%d\n",search(s1,s2));system("pause");}intsearch(chars1[],chars2[]){inti=0,j,len=strlen(s2);while(s1[i]){for(j=0;j<len;j++)if(s1[i+j]!=s2[j])break;if(j>=len)returni;elsei++;}return-1;}14、/*用指針變量輸出構(gòu)造體數(shù)組元素。*/structstudent{intnum;char*name;charsex;intage;}stu[5]={{1001,"lihua",'F',18},{1002,"liuxing",'M',19},{1003,"huangke",'F',19},{1004,"fengshou",'F',19},{1005,"Wangming",'M',18}};main(){inti;structstudent*ps;printf("Num\tName\t\t\tSex\tAge\t\n");/*用指針變量輸出構(gòu)造體數(shù)組元素。*/for(ps=stu;ps<stu+5;ps++)printf("%d\t%-10s\t\t%c\t%d\t\n",ps->num,ps->name,ps->sex,ps->age);/*用數(shù)組下標(biāo)法輸出構(gòu)造體數(shù)組元素學(xué)號(hào)和年齡。*/for(i=0;i<5;i++)printf("%d\t%d\t\n",stu[i].num,stu[i].age);}15、/*建立一種有三個(gè)結(jié)點(diǎn)簡樸鏈表:*/#defineNULL0structstudent{intnum;char*name;intage;structstudent*next;};voidmain(){structstudenta,b,c,*head,*p;a.num=1001;="lihua";a.age=18;/*對結(jié)點(diǎn)成員進(jìn)行賦值*/b.num=1002;="liuxing";b.age=19;c.num=1003;="huangke";c.age=18;head=&a;/*建立鏈表,a為頭結(jié)點(diǎn)*/a.next=&b;b.next=&c;c.next=NULL;p=head;/*輸出鏈表*/do{printf("%5d,%s,%3d\n",p->num,p->name,p->age);p=p->next;}while(p!=NULL);}16、/*輸入一種字符串,判斷其與否為回文?；匚淖址侵笍淖蟮接易x和從右到左讀完全相似字符串。*/#include<stdio.h>#include<string.h>#include<string.h>main(){chars[100];inti,j,n;printf("輸入字符串:\n");gets(s);n=strlen(s);for(i=0,j=n-1;i<j;i++,j--)if(s[i]!=s[j])break;if(i>=j)printf("是回文串\n");elseprintf("不是回文串\n");}17、/*冒泡排序,從小到大,排序后成果輸出到屏幕及文獻(xiàn)myf2.out*/#include<stdio.h>voidfun(inta[],intn){inti,j,t;for(i=0;i<=n-1;i++)for(j=0;j<i;j++)if(a[j]>a[j+1]){t=a[j];a[j]=a[j+1];a[j