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專題26構(gòu)造函數(shù)法解決導(dǎo)數(shù)問題一、多選題1.函數(shù)SKIPIF1<0在SKIPIF1<0上有唯一零點SKIPIF1<0,則()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.已知函數(shù)SKIPIF1<0在SKIPIF1<0上可導(dǎo)且SKIPIF1<0,其導(dǎo)函數(shù)SKIPIF1<0滿足SKIPIF1<0,對于函數(shù)SKIPIF1<0,下列結(jié)論正確的是()A.函數(shù)SKIPIF1<0在SKIPIF1<0上為增函數(shù) B.SKIPIF1<0是函數(shù)SKIPIF1<0的極小值點C.函數(shù)SKIPIF1<0必有2個零點 D.SKIPIF1<03.設(shè)定義在SKIPIF1<0上的函數(shù)SKIPIF1<0滿足SKIPIF1<0,且當(dāng)SKIPIF1<0時,SKIPIF1<0.己知存在SKIPIF1<0,且SKIPIF1<0為函數(shù)SKIPIF1<0(SKIPIF1<0為自然對數(shù)的底數(shù))的一個零點,則實數(shù)SKIPIF1<0的取值可能是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.已知函數(shù)SKIPIF1<0的導(dǎo)函數(shù)為SKIPIF1<0,若SKIPIF1<0對SKIPIF1<0恒成立,則下列不等式中,一定成立的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<05.已知函數(shù)SKIPIF1<0的定義域為SKIPIF1<0,導(dǎo)函數(shù)為SKIPIF1<0,SKIPIF1<0,且SKIPIF1<0,則()A.SKIPIF1<0 B.SKIPIF1<0在SKIPIF1<0處取得極大值C.SKIPIF1<0 D.SKIPIF1<0在SKIPIF1<0單調(diào)遞增6.若存在實常數(shù)SKIPIF1<0和SKIPIF1<0,使得函數(shù)SKIPIF1<0和SKIPIF1<0對其公共定義域上的任意實數(shù)x都滿足:SKIPIF1<0和SKIPIF1<0恒成立,則稱此直線SKIPIF1<0為SKIPIF1<0和SKIPIF1<0的“隔離直線”,已知函數(shù)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0(SKIPIF1<0為自然對數(shù)的底數(shù)),則()A.SKIPIF1<0在SKIPIF1<0內(nèi)單調(diào)遞增;B.SKIPIF1<0和SKIPIF1<0之間存在“隔離直線”,且SKIPIF1<0的最小值為SKIPIF1<0;C.SKIPIF1<0和SKIPIF1<0之間存在“隔離直線”,且SKIPIF1<0的取值范圍是SKIPIF1<0;D.SKIPIF1<0和SKIPIF1<0之間存在唯一的“隔離直線”SKIPIF1<0.7.已知定義在SKIPIF1<0上的函數(shù)SKIPIF1<0,SKIPIF1<0是SKIPIF1<0的導(dǎo)函數(shù),且恒有SKIPIF1<0成立,則SKIPIF1<0SKIPIF1<0A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0二、單選題8.已知數(shù)列SKIPIF1<0滿足SKIPIF1<0,SKIPIF1<0.若SKIPIF1<0恒成立,則實數(shù)SKIPIF1<0的最大值是()(選項中SKIPIF1<0為自然對數(shù)的底數(shù),大約為SKIPIF1<0)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<09.已知函數(shù)SKIPIF1<0且SKIPIF1<0恒成立,則實數(shù)SKIPIF1<0的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<010.已知SKIPIF1<0,若對任意兩個不等的正實數(shù)SKIPIF1<0,SKIPIF1<0,都有SKIPIF1<0恒成立,則a的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<011.已知SKIPIF1<0是定義在SKIPIF1<0上的奇函數(shù),且SKIPIF1<0時SKIPIF1<0,又SKIPIF1<0,則SKIPIF1<0的解集為()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<012.已知偶函數(shù)SKIPIF1<0對于任意的SKIPIF1<0滿足SKIPIF1<0(其中SKIPIF1<0是函數(shù)SKIPIF1<0的導(dǎo)函數(shù)),則下列不等式中成立的是()A.SKIPIF1<0B.SKIPIF1<0C.SKIPIF1<0D.SKIPIF1<013.已知奇函數(shù)SKIPIF1<0的導(dǎo)函數(shù)為SKIPIF1<0,當(dāng)SKIPIF1<0時,SKIPIF1<0,若SKIPIF1<0,則SKIPIF1<0的大小關(guān)系正確的是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<014.設(shè)定義在SKIPIF1<0上的函數(shù)SKIPIF1<0的導(dǎo)函數(shù)為SKIPIF1<0,若SKIPIF1<0,SKIPIF1<0,則不等式SKIPIF1<0(其中SKIPIF1<0為自然對數(shù)的底數(shù))的解集為()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<015.若曲線SKIPIF1<0與曲線SKIPIF1<0存在公切線,則實數(shù)SKIPIF1<0的取值范圍()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<016.丹麥數(shù)學(xué)家琴生(Jensen)是19世紀對數(shù)學(xué)分析做出卓越貢獻的巨人,特別是在函數(shù)的凹凸性與不等式方面留下了很多寶貴的成果.設(shè)函數(shù)SKIPIF1<0在SKIPIF1<0上的導(dǎo)函數(shù)為SKIPIF1<0,SKIPIF1<0在SKIPIF1<0上的導(dǎo)函數(shù)為SKIPIF1<0,若在SKIPIF1<0上SKIPIF1<0恒成立,則稱函數(shù)SKIPIF1<0在SKIPIF1<0上為“凸函數(shù)”.已知SKIPIF1<0在SKIPIF1<0上為“凸函數(shù)”,則實數(shù)SKIPIF1<0的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<017.已知函數(shù)SKIPIF1<0的定義域為SKIPIF1<0,SKIPIF1<0為SKIPIF1<0的導(dǎo)函數(shù).若SKIPIF1<0,且SKIPIF1<0,則不等式SKIPIF1<0的解集為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<018.函數(shù)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,對任意的SKIPIF1<0,都有SKIPIF1<0成立,則不等式SKIPIF1<0的解集為()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<019.已知函數(shù)SKIPIF1<0,若不等式SKIPIF1<0對于任意的非負實數(shù)SKIPIF1<0都成立,求實數(shù)SKIPIF1<0的取值范圍為()A.SKIPIF1<0,SKIPIF1<0 B.SKIPIF1<0,SKIPIF1<0 C.SKIPIF1<0,SKIPIF1<0 D.SKIPIF1<0,SKIPIF1<020.定義在R上的偶函數(shù)f(x)的導(dǎo)函數(shù)為f′(x),若?x∈R,都有2f(x)+xf′(x)<2,則使x2f(x)-f(1)<x2-1成立的實數(shù)x的取值范圍是()A.{x|x≠±1} B.(-1,0)∪(0,1)C.(-1,1) D.(-∞,-1)∪(1,+∞)21.設(shè)函數(shù)SKIPIF1<0在SKIPIF1<0上存在導(dǎo)數(shù)SKIPIF1<0,對任意的SKIPIF1<0,有SKIPIF1<0,且在SKIPIF1<0上有SKIPIF1<0,則不等式SKIPIF1<0的解集是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<022.設(shè)SKIPIF1<0是函數(shù)SKIPIF1<0的導(dǎo)函數(shù),若對任意實數(shù)SKIPIF1<0,都有SKIPIF1<0,且SKIPIF1<0,則不等式SKIPIF1<0的解集為()A.SKIPIF1<0 B.SKIPIF1<0 C.(0,2020] D.(1,2020]23.已知SKIPIF1<0是可導(dǎo)的函數(shù),且SKIPIF1<0,對于SKIPIF1<0恒成立,則下列不等關(guān)系正確的是()A.SKIPIF1<0,SKIPIF1<0 B.SKIPIF1<0,SKIPIF1<0C.SKIPIF1<0,SKIPIF1<0 D.SKIPIF1<0,SKIPIF1<024.已知函數(shù)SKIPIF1<0的導(dǎo)函數(shù)為SKIPIF1<0,SKIPIF1<0為自然對數(shù)的底數(shù),對SKIPIF1<0均有SKIPIF1<0成立,且SKIPIF1<0,則不等式SKIPIF1<0的解集是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<025.函數(shù)SKIPIF1<0是定義在區(qū)間SKIPIF1<0上的可導(dǎo)函數(shù),其導(dǎo)函數(shù)SKIPIF1<0,且滿足SKIPIF1<0,則不等式SKIPIF1<0的解集為()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<026.已知函數(shù)f(x)的定義域為R,f(-1)=3,對任意x∈R,f′(x)>3,則f(x)>3x+6的解集為()A.(-1,+∞) B.(-1,1) C.(-∞,-1) D.(-∞,+∞)27.奇函數(shù)SKIPIF1<0定義域為SKIPIF1<0,其導(dǎo)函數(shù)是SKIPIF1<0.當(dāng)SKIPIF1<0時,有SKIPIF1<0,則關(guān)于SKIPIF1<0的不等式SKIPIF1<0的解集為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<028.若對任意的SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0恒成立,則a的最小值為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<029.函數(shù)SKIPIF1<0是定義在SKIPIF1<0上的奇函數(shù),其導(dǎo)函數(shù)記為SKIPIF1<0,當(dāng)SKIPIF1<0時,SKIPIF1<0恒成立,若SKIPIF1<0,則不等式SKIPIF1<0的解集為()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<030.已知SKIPIF1<0、SKIPIF1<0,函數(shù)SKIPIF1<0恰有兩個零點,則SKIPIF1<0的取值范圍()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<031.定義在R上的函數(shù)SKIPIF1<0滿足SKIPIF1<0,則下列不等式一定成立的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<032.已知函數(shù)SKIPIF1<0,其中SKIPIF1<0,若對于任意的SKIPIF1<0,且SKIPIF1<0,都有SKIPIF1<0SKIPIF1<0成立,則SKIPIF1<0的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<033.設(shè)SKIPIF1<0是定義在SKIPIF1<0上的偶函數(shù),SKIPIF1<0為其導(dǎo)函數(shù),SKIPIF1<0,當(dāng)SKIPIF1<0時,有SKIPIF1<0恒成立,則不等式SKIPIF1<0的解集為()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0三、解答題34.已知函數(shù)SKIPIF1<0.(1)討論SKIPIF1<0的單調(diào)性;(2)若SKIPIF1<0,SKIPIF1<0是方程SKIPIF1<0的兩個不同實根,證明:SKIPIF1<0.35.已知函數(shù)SKIPIF1<0在點SKIPIF1<0處的切線方程為SKIPIF1<0.(1)求實數(shù)SKIPIF1<0,SKIPIF1<0的值﹔(2)若函數(shù)SKIPIF1<0,試討論函數(shù)SKIPIF1<0的零點個數(shù).36.已知實數(shù)SKIPIF1<0,函數(shù)SKIPIF1<0,SKIPIF1<0.(1)討論函數(shù)SKIPIF1<0的單調(diào)性;(2)若SKIPIF1<0是函數(shù)SKIPIF1<0的極值點,曲線SKIPIF1<0在點SKIPIF1<0?SKIPIF1<0(SKIPIF1<0)處的切線分別為SKIPIF1<0?SKIPIF1<0,且SKIPIF1<0?SKIPIF1<0在y軸上的截距分別為SKIPIF1<0?SKIPIF1<0.若SKIPIF1<0,求SKIPIF1<0的取值范圍.37.設(shè)函數(shù)SKIPIF1<0,SKIPIF1<0.(1)討論函數(shù)SKIPIF1<0的單調(diào)性;(2)如果對于任意的SKIPIF1<0,都有SKIPIF1<0成立,試求SKIPIF1<0的取值范圍.38.已知函數(shù)SKIPIF1<0,SKIPIF1<0.(1)討論函數(shù)SKIPIF1<0的單調(diào)性;(2)若當(dāng)SKIPIF1<0時,方程SKIPIF1<0有實數(shù)解,求實數(shù)SKIPIF1<0的取值范圍.39.給出如下兩個命題:命題SKIPIF1<0,SKIPIF1<0;命題SKIPIF1<0已知函數(shù)SKIPIF1<0,且對任意SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,都有SKIPIF1<0.(1)若命題SKIPIF1<0為假,求實數(shù)SKIPIF1<0的取值范圍.(2)若命題SKIPIF1<0為假,SKIPIF1<0為真,求實數(shù)SKIPIF1<0的取值范圍.40.已知
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