新高考數(shù)學(xué)二輪復(fù)習(xí)分層訓(xùn)練專題03 不等式（原卷版）

答案第=page11頁，共=sectionpages22頁解密03講：不等式【練基礎(chǔ)】一、單選題1．（2022·四川·中和中學(xué)高三模擬）若SKIPIF1<0，則下列不等式一定成立的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·廣東湛江·高三階段練習(xí)）已知SKIPIF1<0，則下列說法正確的是（

）A．若SKIPIF1<0，則SKIPIF1<0 B．若SKIPIF1<0，則SKIPIF1<0C．若SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0 D．若SKIPIF1<0，SKIPIF1<0，則SKIPIF1<03．（2021·安徽·高三階段練習(xí)（文））已知a，b>1且a≠b，下列各式中最大的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·重慶·高三階段練習(xí)）關(guān)于SKIPIF1<0的不等式SKIPIF1<0恒成立，則實數(shù)SKIPIF1<0的取值范圍為（

）.A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2023·全國·高三專題練習(xí)）對任意不相等的兩個正實數(shù)SKIPIF1<0，SKIPIF1<0，滿足SKIPIF1<0的函數(shù)是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<06．（2023·內(nèi)蒙古赤峰·高三階段練習(xí)（文））已知實數(shù)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則下列說法中，正確的是（

）．A．SKIPIF1<0 B．存在a，b，使得SKIPIF1<0C．SKIPIF1<0 D．存在a，b，使得直線SKIPIF1<0與圓SKIPIF1<0相切7．（2023·四川資陽·模擬預(yù)測（文））已知a，b均為正數(shù)，且SKIPIF1<0，則SKIPIF1<0的最小值為（

）A．8 B．16 C．24 D．328．（2022·山東聊城·高一期中）已知SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，不等式SKIPIF1<0恒成立，則正實數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0二、多選題9．（2022·福建·莆田一中高三階段練習(xí)）已知關(guān)于SKIPIF1<0的不等式SKIPIF1<0解集為SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．不等式SKIPIF1<0的解集為SKIPIF1<010．（2022·湖北·咸豐春暉學(xué)校高三階段練習(xí)）若SKIPIF1<0，則下列不等式中一定不成立的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<011．（2022·安徽·合肥一中高三階段練習(xí)）不等式SKIPIF1<0對任意SKIPIF1<0恒成立，則下列關(guān)系正確的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<012．（2022·山東聊城·高三模擬）設(shè)SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，則下列說法中正確的是（

）A．SKIPIF1<0有最小值SKIPIF1<0 B．SKIPIF1<0有最大值SKIPIF1<0C．SKIPIF1<0有最大值SKIPIF1<0 D．SKIPIF1<0有最小值SKIPIF1<0三、填空題13．（2022·廣東·廣州市番禺區(qū)大龍中學(xué)高三階段練習(xí)）若SKIPIF1<0則SKIPIF1<0的最小值是__________.14．（2022·河北·高三階段練習(xí)）若關(guān)于SKIPIF1<0的不等式SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)有解，則實數(shù)SKIPIF1<0的取值范圍是______.15．（2022·江蘇·高三課時練習(xí)）在SKIPIF1<0中，設(shè)邊SKIPIF1<0所對的角為SKIPIF1<0，若SKIPIF1<0，則SKIPIF1<0的最大值為________．16．（2022·山西臨汾·高三階段練習(xí)）已知SKIPIF1<0，若SKIPIF1<0是SKIPIF1<0與SKIPIF1<0的等比中項，則SKIPIF1<0的最小值為__________．四、解答題17．（2022·陜西·興平市南郊高級中學(xué)高三階段練習(xí)）已知函數(shù)SKIPIF1<0，SKIPIF1<0的解集為SKIPIF1<0或SKIPIF1<0.(1)求實數(shù)SKIPIF1<0、SKIPIF1<0的值；(2)若SKIPIF1<0時，求函數(shù)SKIPIF1<0的最大值.18．（2022·江蘇·句容碧桂園學(xué)校高三開學(xué)考試）已知不等式SKIPIF1<0的解集為SKIPIF1<0，不等式SKIPIF1<0的解集為SKIPIF1<0．(1)若SKIPIF1<0，不等式SKIPIF1<0的解集為SKIPIF1<0，求不等式SKIPIF1<0的解集；(2)SKIPIF1<0，SKIPIF1<0，求a的取值范圍．19．（2020·河南新鄉(xiāng)·高二期中（文））（1）比較SKIPIF1<0與SKIPIF1<0的大小（2）已知SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，證明：SKIPIF1<020．（2021·江西·高二階段練習(xí)（理））設(shè)函數(shù)SKIPIF1<0.(1)當(dāng)SKIPIF1<0時，求關(guān)于SKIPIF1<0的不等式SKIPIF1<0的解集；(2)若SKIPIF1<0，當(dāng)SKIPIF1<0時，不等式SKIPIF1<0恒成立，求實數(shù)SKIPIF1<0的取值范圍.21．（2023·廣東·惠來縣第一中學(xué)高三階段練習(xí)）已知實數(shù)SKIPIF1<0，SKIPIF1<0，(1)若SKIPIF1<0，求SKIPIF1<0的最小值．(2)若SKIPIF1<0，求SKIPIF1<0的最大值與SKIPIF1<0的最小值；(3)求SKIPIF1<0的最大值，并求此時x的值；22．（2022·浙江·杭十四中高三專練）已知函數(shù)SKIPIF1<0.(1)當(dāng)SKIPIF1<0時，解關(guān)于SKIPIF1<0的不等式SKIPIF1<0.(2)不等式SKIPIF1<0對任意SKIPIF1<0恒成立，求實數(shù)SKIPIF1<0的取值范圍.【提能力】一、單選題1．（2022·浙江·鎮(zhèn)海中學(xué)高三期中）已知SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·天津市第七中學(xué)高三期中）若SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0，SKIPIF1<0，SKIPIF1<0的大小關(guān)系是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·山東聊城一中高三期中）對于實數(shù)a，b，c，下列命題中正確的是（

）A．若SKIPIF1<0，則SKIPIF1<0B．若SKIPIF1<0，則SKIPIF1<0C．若SKIPIF1<0，則SKIPIF1<0D．若SKIPIF1<0，則SKIPIF1<04．（2022·江蘇泰州·高三期中）對任意正數(shù)x，y，不等式x（x+y）≤a（x2+y2）恒成立，則實數(shù)a的最小值為（）A．SKIPIF1<0 B．SKIPIF1<0﹣1 C．SKIPIF1<0+1 D．SKIPIF1<05．（2022·江西贛州·二模（理））在等差數(shù)列SKIPIF1<0和等比數(shù)列SKIPIF1<0中，有SKIPIF1<0，且SKIPIF1<0，則下列關(guān)系式中正確的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2022·陜西·西安市第三中學(xué)高三階段練習(xí)）已知正數(shù)SKIPIF1<0滿足SKIPIF1<0，則SKIPIF1<0的最小值為（

）A．1 B．SKIPIF1<0 C．2 D．SKIPIF1<07．（2022·貴州貴陽·高三階段練習(xí)（理））已知函數(shù)SKIPIF1<0的圖像恒過一點P，且點P在直線SKIPIF1<0的圖像上，則SKIPIF1<0的最小值為（

）A．4 B．6 C．7 D．88．（2022·山東省青島第五十八中學(xué)高三期中）已知對任意SKIPIF1<0，且SKIPIF1<0，SKIPIF1<0恒成立，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0二、多選題9．（2022·廣東·廣州市第九十七中學(xué)高三階段練習(xí)）下列幾種說法中，正確的是（

）A．“SKIPIF1<0”是“SKIPIF1<0”的充要條件B．命題“SKIPIF1<0，SKIPIF1<0”的否定是“SKIPIF1<0，SKIPIF1<0”C．若不等式SKIPIF1<0的解集是SKIPIF1<0，則SKIPIF1<0的解集是SKIPIF1<0D．“SKIPIF1<0”是“不等式SKIPIF1<0對一切SKIPIF1<0都成立”的充要條件10．（2022·湖南經(jīng)緯實驗學(xué)校高三期中）以下命題為真命題的是（

）A．不等式SKIPIF1<0的解集為SKIPIF1<0.B．方程SKIPIF1<0有異號根的充要條件是SKIPIF1<0C．若SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0D．“SKIPIF1<0”是“SKIPIF1<0”的充分不必要條件11．（2022·重慶十八中高三階段練習(xí)）不等式SKIPIF1<0對任意SKIPIF1<0恒成立，則（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<012．（2022·遼寧·東北育才學(xué)校高三階段練習(xí)）已知正實數(shù)SKIPIF1<0，滿足SKIPIF1<0，則（

）A．SKIPIF1<0的最大值為1 B．SKIPIF1<0的最小值為4C．SKIPIF1<0的最小值為1 D．SKIPIF1<0的最小值為18三、填空題13．（2022·福建泉州·高三期中）已知函數(shù)SKIPIF1<0與函數(shù)SKIPIF1<0有公共點，則SKIPIF1<0的最小值為______.14．（2023·全國·高三專題練習(xí)）若SKIPIF1<0，使SKIPIF1<0成立，則實數(shù)SKIPIF1<0的取值范圍是______________．15．（2022·福建省福州第十一中學(xué)高三期中）已知SKIPIF1<0，SKIPIF1<0，直線SKIPIF1<0與直線SKIPIF1<0垂直，則SKIPIF1<0的最小值是___________.16．（2022·安徽·合肥一六八中學(xué)高三階段練習(xí)）已知函數(shù)SKIPIF1<0，SKIPIF1<0為直線SKIPIF1<0上一點，過點SKIPIF1<0作函數(shù)SKIPIF1<0圖象的兩條切線，切點分別為A，B，則SKIPIF1<0的最小值為____________．四、解答題17．（2022·陜西·永壽縣中學(xué)高三階段練習(xí)（文））已知命題p：SKIPIF1