Buffers and Titrations South Kingstown High Shool:緩沖器和滴定南金斯敦高中_第1頁
Buffers and Titrations South Kingstown High Shool:緩沖器和滴定南金斯敦高中_第2頁
Buffers and Titrations South Kingstown High Shool:緩沖器和滴定南金斯敦高中_第3頁
Buffers and Titrations South Kingstown High Shool:緩沖器和滴定南金斯敦高中_第4頁
Buffers and Titrations South Kingstown High Shool:緩沖器和滴定南金斯敦高中_第5頁
已閱讀5頁,還剩12頁未讀, 繼續(xù)免費閱讀

下載本文檔

版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請進(jìn)行舉報或認(rèn)領(lǐng)

文檔簡介

1、buffersa buffer in actiondefinition of a bufferna buffer solution is one which resists changes in ph when small quantities of an acid or a base are added to it.vthe most important way that the ph of the blood is kept relatively constant is by buffers dissolved in the blood. h2co3 + h2o hco3- + oh-hc

2、o3- + h+ h2co3hco3- + 3oh h2o + h2co3vwhen a substance acts as both an acid and a base such as hco3- does, it is called amphoteric.how do buffer solutions work?na buffer solution contains a weak acid and base, which removes any hydrogen ions or hydroxide ions that are add keeping the ph constant. (n

3、ot neutral)nthe bicarbonate buffer:weak acid weak base h2co3 + h2o hco3- + oh-another buffer solutionnammonia is a weak base, and the position of this equilibrium will be well to the left:nany added hydrogen ions will react with the ammonia to make more of the conjugate acid, maintaining the ph.anot

4、her buffer solutionsnany added oh- ions will react with the weak acid to make the conjugate base and again maintain a constant ph.determination of the ph of a buffer solutionnexample: what is the ph of a solution of 0.11 m nac2h3o2 and 0.090 m hc2h3o2?(ka = 1.8 x 10-5)hc2h3o2 c2h3o2- + h+initial0.09

5、0.110change-x+x+xequil.09-x0.11 +xxka = x (0.11) /.09-x x = 1.47 x 10-5, ph = 4.83n(buffered solution will have a very small dissociation so + or x can be ignored)preparing buffer solutionsnthe henderson-hasselbalch equation gives the ratio of weak acid to base needed to maintain a constant ph.nph =

6、 pka + log a-/ha(the ph can be approximated: ph = pka +1preparing buffers1.example. what is the mole ratio of acetic acid to acetate ion needed to prepare a buffer solution at a ph = 5.00? ka= 1.8 x 10-5ka = h+ a- = h+ mol c2h3o2- ha mol hc2h3oph = 5 so, h+ = 1 x 10-5 mol c2h3o2- = h+ = 1x 10-5 = .5

7、6mol hc2h3o ka 1.8 x 10-5preparing buffers2.what is the ph of a solution containing 0.11 m of sodium acetate and 0.090 m acetic acid? ka = 1.8 x 10-5nph = pka + log a-/haph = 4.74 + log (0.11mol a-) (0.090 mol ha)ph = 4.83ntitration of a strong acid by a strong basethe equivalence point occurs at 25

8、.00 ml added base with a ph of 7.0.titrationsntitration of a weak acid by a strong baseqthis can be divided into four regions1)before the titration begins: this is simple a solution of weak acid2)during the titration, but before the equivalence point: the solution is a buffer3)at the equivalence poi

9、nt: the solution contains a salt of the weak acid, and hydrolysis can occur4)past the equivalence point: the excess added oh- is used to determine the ph of the solutiontitrations the titration curve for the titration of 25.00 ml of 0.200 m acetic acid with 0.200 m sodium hydroxide. due to hydrolysi

10、s, the ph at the equivalence point higher than 7.00.buffered regionntitration of a weak base by a strong acidqthis is similar to the titration of a weak acid by strong baseqagain dividing into four regions1)before the titration begins: this is a solution of a weak base in water2)during the titration

11、, but before the equivalence point: the solution is a buffer3)at the equivalence point: the solution contains the salt of the weak base, and hydrolysis can occur4)past the equivalence point: excess added h+ determines the ph of the solutiontitrations titration curve for the titration of 25.00 ml of

12、0.200 m nh3 with 0.200 m hcl. the ph at the equivalence point is below 7.00 because of the hydrolysis of nh4+.buffered regionntitration curves for diprotic acidsqthe features are similar to those for monoprotic acids, but two equivalence points are reachedthe titration of the diprotic acid h2a by a

13、strong base. as each equivalence point is reached, the ph rises sharply.titrationsna few general comments about indicators can be madeqmost dyes that are acid-base indicators are weak acids, which can be represented as hinqthe color change can be represented as:color)(another color) (oneform base form acid )()()(hininhkaqinaqhaqhinhintitrationsqthe color change will “appear” to the human eye near the equivalence point of the indicatorqat the equivalence point, the concentration of the acid and base form are equal,

溫馨提示

  • 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
  • 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
  • 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
  • 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
  • 5. 人人文庫網(wǎng)僅提供信息存儲空間,僅對用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對任何下載內(nèi)容負(fù)責(zé)。
  • 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請與我們聯(lián)系,我們立即糾正。
  • 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時也不承擔(dān)用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。

評論

0/150

提交評論