(完整版)軟件測試題目與答案

1、軟件測試課堂測驗第一次測驗：Consider an application App that takes two inputs name and age, where name is a nonempty string containing at most 20 alphabetic characters and age is an integer that must satisfy the constraint 0<age< 120. The App is required to display an error message if the input value provid

2、ed for age is out of range. The application truncates any name that is more than 20-character in length and generates an error message if an empty string is supplied for name.（1） Please find out the equivalence classes等價類）.（30 分）（2） Construct test cases using the equivalence classes derived M）（20 分）

3、答案：Consider a method fp, brief for findPrice, that takes two inputs code and qty. The item code is represented by the integer code and the quantity purchased by another integer variable qty. fp accesses a database to find and display the unit price, the description, and the total price of the item c

4、orresponding to code. fp is required to display an error message, and return, if either of the two inputs is incorrect. Assuming that an item code must be in the range 9 9 999 and quantity in the range 1- 100.Please give your test cases using boundary-value analysis50 分） 答案：第二次：1 .Develop a decision

5、 table for the descriptions belowNo charges are reimbursed報銷）to the patient until the deductible（扣除） has been met. After the deductible has been met, the amount to be reimbursed depends on whether or not the doctor or hospital is a "Preferred Provider." For preferred providersDoctor's

6、office visits are reimbursed at 65% and Hospital visits are reimbursed at 95%. For other providers reimburse 50% for Doctor's Office visits or 80% for Hospital visits.2 .Develop a decision table for the YesterDate function.答案：第三次:Cause-Effect Testing In a given network, the sendfile command is u

7、sed to send a file to a user on a different file server. The sendfile command takes three arguments: the first argument should be an existing file in the sender" s home directory, the second argument should be the name of the receiver" s file server, and the third argument should be the re

8、ceiver" s userid. If all the arguments are correct, then the file is successfully sent; otherwise the sender obtains an error message.答案：中國象棋走馬下法：1 .如果落點在棋盤外，則不移動棋子；2 .如果落點與起點不構成日字形，則不移動棋子；3 .如果落點處有自己放棋子，則不移動棋子；4 .如果在落點方向的鄰近交叉點有棋子（絆馬腿），則不移動棋子；5 .如果不屬于1-4,且落點處無棋子，則移動棋子；6 .如果不屬于1-4,且落點處為對方棋子（非老將）

9、，則移動棋子并除去對方棋子7 .如果不屬于1-4,且落點處為對方老將，則移動棋子，并提示戰(zhàn)勝對方，游戲 結束。請畫出因果圖，并轉換成判定表答案：Consider a web page with three distinct sections(Top, Midddle, and Bottom) that can be individually shown or hidden by the user. Please use orthogonalarray testing to test the interactions of the different sections.L4 (25)答案: 第四

10、次：某電力公司有A、B、C、D共四類收費標準，并規(guī)定：居民用電每月200度以下按A類收費，200度以上按B類收費。動力電以每月1萬度為分界：非高峰用電不足1萬度按B類收費，達到或超過1萬度按C類收費 高峰用電不足1萬度按C類收費，達到或超過1萬度按D類收費。 給出控制流圖，并設計滿足條件組合覆蓋的測試用例 答案：X80 andUOandQuestion 21.給出控制流圖。2.給出判定覆蓋、條件 覆蓋、條件組合覆蓋和 路徑覆蓋的測試用例。Question 31 ,給出控制流圖“2.給出語句覆蓋、int logicExample(int x, int y)int magic=0;if(x>

11、0 && y>0)magic = x+y+10; 語句塊 1 else判定覆蓋、條件覆 蓋.條件組合覆蓋 和路徑覆蓋的測試 用例口magic = x+y-1。; 語句塊2 )if(magic < 0)( magic = 0;語句塊3)return magic; "語句塊4答案:第五次:Question 1Void Do(intX, int A, int B, int C)要求：1 .畫出基本的控 制流圖和詳細的控制流圖口 2分別計算1中的圈復雜度.3 .給出獨立路 徑，并針對獨立 路徑設訶測試用 例1234567891011while(X+<10)rf(A>1)| (B-0) C=C/A;elseif(C<0) && (X>1)X=X+1;A=B+C;要求：1 .畫出基本的控制流圖 和詳細的控制流圖口2 .分別計算1中的圈芨 雜度U;給過獨立路徑，并針 對獨立路徑設計測試用 例float triangfeTypeffloat a,float b.float c) (1 float I;2 if(a+b<=c | a+c<=b | tync&l