![c語言程序填空題題庫_第1頁](http://file4.renrendoc.com/view/c367cd8bcd0a61ce821b08cd33d3ebcb/c367cd8bcd0a61ce821b08cd33d3ebcb1.gif)
![c語言程序填空題題庫_第2頁](http://file4.renrendoc.com/view/c367cd8bcd0a61ce821b08cd33d3ebcb/c367cd8bcd0a61ce821b08cd33d3ebcb2.gif)
![c語言程序填空題題庫_第3頁](http://file4.renrendoc.com/view/c367cd8bcd0a61ce821b08cd33d3ebcb/c367cd8bcd0a61ce821b08cd33d3ebcb3.gif)
![c語言程序填空題題庫_第4頁](http://file4.renrendoc.com/view/c367cd8bcd0a61ce821b08cd33d3ebcb/c367cd8bcd0a61ce821b08cd33d3ebcb4.gif)
版權說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權,請進行舉報或認領
文檔簡介
試卷編號:10097所屬語言:TYirboC試卷方案:cxl試卷總分:1260分共有題型:1種ー、程序填空共126題(共計1260分)第1題(10.〇分)題號:425尸 - 【程序填空】功能:當輸入“Zド的時候輸出為“25ド#include<stdiah>#definemax100main0intffcnW,i,j,k可for(i=05i<=[?];i44)f[i]=Qf[[?l>1;for(j=iTj+4)f[i][?]f田;printf('%P^10c^ol0d\ri",k,rqf畫);}答案:.m.k-1或k-1—或=1+第2題(10.〇分) 題號:466產(chǎn) 【程序填空】功能:用二分法求方程2KA巾XA2母6=0在(TQ1Q)之間的根,其中X"n代表XWn次方。ツ#include<irath.h>main0{floatxO,xl,x2,fxO,fxl,fx2;doprintf("Enterxl&x2");scanf("%f,%f",&xl,&x2;fxlヨ1*(Q*xl—4)*xl-H)—fx,fx2=x2*(Q*x2-4)*x2-t-3)—}while(fxl*fx2[?]);doxO=(xl+x2)々fxO=xO*((2*xO-4)*x0+^)—fx,if(fxO*fxl[?])x2=xQfx2=fxQelsexl=xQfxl=fxQwhile([?]>=le—9;printf(nx=^i2N",xQ;}答案:.>0.<0fabs(fx(J)功能:不用第三個變量,實現(xiàn)兩個數(shù)的對調(diào)操作。#include<stdiah>main〇inta,Uscanf("%i%jn,&a, ;printf("左%I a,坊;S=[?];/k'k'k'k'k'k'k'k'k^'kSpN^vk'ivk'k'k'k'k'k'k*///$c?バ??バ?**SR^E**********^/7s=[?];printf("即始,片小p",a,0;答案:1).》.a—b或a—b》.a—b或a—b3.a-b或a-b(10.〇分)題號:483功能:對數(shù)組A中的N(0(や100個整數(shù)從小到大進行連續(xù)編號,輸出各個元素的編號。要求不能改變數(shù)組A中元素的順序,且相同的整數(shù)要具有相同的編號。例如:數(shù)組是:A0,3,47,3,5,⑸則輸出為:61,2,5,1,3,4main0inti,j,k,n,m=l,r=l,a0[100]=(0(;printf("Pleaseentern:ツ;scanff%!",&rj);for(i=0;i<h;i-H){printffa%J]=",i);scanfC%i",&a[O]國);v4iile([?])for(i=0;i<h;i-H)ifqdora=o)^rk'k"k'k'k"k'k'k-k'kqp^Q^'k'k'k'k-k'k'k-k'k'k^k=i;for(j=i;j<h;j-H)ifkDO田=0瞰a⑼田。ゆ図)[?1;aDOK=r-H-;mH-;for(j=0;j<h;j-H)ifQCODH=O齦:a⑹[j]=^UJ図)aDO[j]=aQ]図;mH-;for(i=0;i<h;i-H)printfCa猛以i,a凹[i],aDO[i]);答案:1).mCn或n5m1).mCn或n5m2.break(10.〇分)題號:458【程序填空】功能:用等分法在有序的循環(huán)數(shù)組中,找到最小元素的位置。intcyclicmin(intx口,intrj)intleftintright=n—1;intmidせ*******SF^2E**********^/while([?])mid=(left+right)if(x6fHe<x[right])^/$T5*rせ1*******sfy^E*********1*"5^/^elsereturnleft;#include<stdiah>voidmainfyoicj){intx。={2Q23,2&35,39,40,42,&10,15,17,19};intn=sizeof位/sizeof(int);intloc,i;printf(1\nFindCyclicMinimum1);printf(N =);printff\iXpGivenArraySortedinCyc1icFashion:Xp1);for(i=?i<n;i-H)printfCW,x[i]);loc=cyclicmin&rj);printf("XfiXrMinirnimislocatedatx泡=%d",loc,x[locO);}答案:.left<right或right>left.right=mid.left=mid+l或!eft=14tnid第6題(10.〇分)題號:34產(chǎn) 【程序填空】功能:以下程序的功能如圖1)。 一?/#inc1ude<coniah>#include<stdiah>★★★*/floatfun([?],intrj)【?】;floatxa=0,s;for(j=Qj<^j-H-)xa4=x[J]ん/k'k'k'k'k'k'k'k'k'k'kヾpH下k"k'k*k'k'k'k'k'k'k/[?];forj<n;j-H-)s+=(KDJ-xai)*K-xaD/h;/k'k'k'k'k'k'k'kit'k'kSp葭サ*をバ******/[?];}main()Ifloatx[100]={193.199,195.673,195.757,196051,196092,196596,196579,196763);clrscr();printfC%f\nu,fun-8);}答案:D.floatx?;騠loat*j.s=0或s=0.0勺.returns或return(s)第7題(10.〇分) 題號:430/【程序填空】功能:計算一元二次方程的根。 */#include<stdiah>#include[?]main〇floata,b,Gdisc,xl,x2,realpart,imagpart;scanf ",&a,&b,&c);printf("theequation1);/i'k'k'k'k'k'k'k'k'k'kSpN^^'k'k'k'k'k'k'k'k'k'k/if([?]<=le-6)printf("isnotquadraticXp1);elsedisG=b*b-4*a*c;if(fabs&is0<=le-^printf("hastw)equalroots:%-&4f\p",-^/(2*a));//9r?バ??せ?**SJ^Y2E**********^/elseif([?])xl=(-tH-sqrt@isc))/Q*ai);x2=(-b-sqrt@isc))/Q*a);printfC'hasdistinctrealroots:%814fand%4fxp",xl,x2;}elserea1part=H)/(2*a);imagpart=sqrt(-disc)/(2*a);printf("hasccmplexroots:\p");printf('燈4f^4fN",realpart,imagpart);printf。加4f-%4fi\p",realpart,imagpart);答案:.<nath.h>.fabs團fabsQisc)>le-6或le-6<fabsfciisq)第8題(10.0分)題號:410【程序填空】功能:有n個整數(shù),使其前面各數(shù)順序向后移m個位置,最后m個數(shù)變成最前面的m個數(shù)main0intnumberU(J],n,n)i;printf("thetotalnumbersis:ツ;scanfC%!",&rj);printf("backmツ;scanf(1%!",&0;for(i=Qi<h-l;i+0scanf(1%],",&number[i]);scanff%i",&mirber[h-1]);/ck'k'k'k'k'k'k'k'k'kSONja'k'k'k'k'k?十**'k/move([?]);for(i=Qi<h-l;i-H)printff%!H,number[i]);printfnumber[n-1]);/r**********SR^ZE*******メ?*サn?ve([?])intn,n)array[20];int*p>array_en(J/失火?火?火央/array_encM([?]);for¢p=array+n—1;p>array;p-4/rk'k'k'k'k'k'k'k'k'kSPM^^'^火★火女火★火★夫/*?(【?】);*array=array_end,m-;if(ii>Q)moveQrray,n,n);}答案:.number,n,m.array,n,m.array+n—1或array+n—1④.p-1或p-1第9題(10.〇分)題號:15個 功能:分別求出ー批非零整數(shù)中的偶數(shù)、奇數(shù)的平均值,用零作為終止標記。main〇intx,i=O,j=Qfloatsl=0,s2=0,avl,a總while([?])if(x^=o{sl=sl+x;H4;}/3(十?)吠タ宗宗*左*國?C^rk'k'k'k'k'k'k'k'k'k/s2=s2+x;/vk'k'k'k'k'k"k'k**S^>NJE^!★火京也?^***/avl=^]/i;elseavlfif(j!=O^/9fVr^nfc******^^^^^^********1^/elseav2=Qprintf。〇ushujunzhi:%7.2f,jishujunzhi:%7.2f\nH,avl,avの;}答案:.x!=0或x.e1se或elseif期2=1)或e1seif的0=(5或if妙。scanfC%!",則④.av2=s2/j第10題(10.0分)題號:456【程序填空】功能:利用指向結構的指針編寫求某年、某月、某日是第幾天的程序,其中年、月、日和年天數(shù)用結構表示。main0[?]dateinty,rr;d,"}[?];intk,f,aロ0=0L28,31,30,31,30,31,31,30,31,30,31};printfffdatey,rqわッ;scanf泡&xy,&x.n)&x.d);Xc幽=08&x例00!=0||x財00=。/k'k'k'k'k'k'k'k'k^'kSpNJ^vk'k'k'k'k'k'k'k'k*/if僅n<lIIxrri>12||xd<liIxd>a[xm-1])exit?;for僅n==xd,k=Qk<xm-1;leH)xn4=^R;/rk'k'k'k'k'k'k'k'k'ksp^j^vk'k'k'k'k'k'k'k'k'k/printf("n=%Nn",[?]);答案:1).structx.f④.xn第11題(10.〇分)題號:462【程序填空】功能:把字符串中所有的字母改寫成該字母的下ー個字母,最后ー個字母z改寫成字母a,大字母仍為大寫字母,小寫字母仍為小寫字母,其它的字符不變。例如:原有的字符串為:"Mi123xyZ,調(diào)用該函數(shù)后,串中的內(nèi)容為:“Na123yz^o#include<stringh>#include<stdiah>#include<ctypeh>#defineN81main()charaN,*s;printf("Enterastring: 11);gets(a);printf(,rTheoriginalstringis: ");puts(a);//9r?バ??せ?**SJ^Y2E**********^/whileビ。*s=a;elseif(*s—Z)*s=^A;elseif(isalpha(*s))/?rk'k'k'k'k'k'k'k'k'kSP^^^火*宗火★宗宗夫宗夫/せ?*バ*****Sf^2E***********:^//printf(1rThestringaftermodified:ツ;puts(a);答案:.s=a.*s+=l或*U*s+l或せs)"H"或44-(*s).s44"或s=s4-!或44-s或s=s+1第12題(10.〇分)題號:27 【程序填空】功能:統(tǒng)計ー個字符串中的字母、數(shù)字、空格和其它字符的個數(shù)。#includenstdiah11main〇charsi[80];inta[4]={Of;intk;バ?*バ***sp^2E**********:^/gets(si);/k'k'k'k'k'k'k'k'k'k'kspx^ck'k'k'k'k'k'k'k'k'k/puts(si);for0<=Q-leH)printfC%d",a図);voidfunfcharsロ,intb0)inti;for(i=Qs[i]!=\(r;i4H)if(a<=s[i]8&s[i]<=zITA<=s[i]8&sZ)/**********SFAZE**********シelseif([?])bDJ+Hy^-k'k'k'k'k'k'k'k'k'k^p^^^'k"k'k'k'k'k'k'k'k'k/elseif([?])else答案:.voidfunfcharsQ,intbロ).fun(si,a)5.'じ<=s[i]<3&s[i]Wタ或s[i]?(/8&s[i]<=タ或’(/<s=s[i]跟‘夕>=s[i]或s[i]*(X8&.,夕―[i]或48<&=sEC8&s[i]V=57或s[i]x!88&s[i]<S=57或48^[i] 57>=sEi]或sEi]>=48S&57>=sD]或!(x<48||x>57)或!(x</(XIIx>'9)4).sEi]=''或sEi]=32第13題(10.〇分) 題號:452尸 功能:從鍵盤輸入若干行字符,輸入后把他們存儲到ー磁盤文件中。在從該文件中讀出這些數(shù)據(jù),將其中的小寫字母轉換成大寫字母后在屏幕上輸出。#includeHstdiah1'#defineN100main0{FILE*fpcharc,*p,s図[20];inti,ヰprintf("n=i1);scanf&rj);if(jKl[?]n^)exit〇;printf("Input%!string\p",rj);for(i=Qi<h;i44)scanf(%",s[1]);fp=fopen("text",[?]);for(i=Q冋i44)P=sLi];whilegp!=\p")if(ferror(fp))fputc([?),fp);fclose(fpl;printf//9c*****バ***SP^2E**********'5^Zfp=fopen("text",[?]);汕ile(Q=fgetc(fp))!=8工)ifばa'z)c—1-3^putchar?;fclose(fp);答案:D.II."w1.*pH-4),"r"第14題(10.0分) 題號:469【程序填空】功能:用遞歸法將一個整數(shù)n轉換成字符串,例如輸入483,應輸出對應的字符串"483"=n的位數(shù)不確定,可以是任意位數(shù)的整數(shù)。#include<stdiah>voidconvert(intrj)inti;convert(i);y^-k'k'k'k'k'k'k'k'k'k^p^^^'k"k'k'k'k'k'k'k'k'k/putchar );main〇intnumber;printf(,r\pInputanintegerツ;printf?Output:ツ;ifSumbeKOputchar(—);[?];convertSunbei);答案:D.i=n/103).nimber=-nun±)er第15題(10.〇分) 題號:14【程序填空】功能:輸出100到1000之間的各位數(shù)字之和能被15整除的所有數(shù),輸出時每10個一行。main0intn)n,k,i=Qfor(n=100jm5=100qmH)火?火火太?引)隕^/ヨ水火火火火?*'k/do/vk'k'k'k'k'k'k'k'k'ksp魔をvk'k'k'k'k'k'k'k'k*/i【?】;n^/iqif蜘!5=?printfC%d",n);i++;y^rk'k"k"k'k'k-kirk'kQp^Q^kicic'k'k-k'k-k-k-k'k^/if(i%LD[?];答案:1).冋ム.叱!0或e40*10或n-10*(h/LCj).while(h>0或while標ii)或while(ri=0或whileユヨj).printfC\n')第16題(10.〇分)題號:397【程序填空】功能:兩個乒乓球隊進行比賽,各出三人。甲隊為a,he三人,乙隊為x,y,z三人。已抽簽決定比賽名單。有人向隊員打聽比賽的名單。a說他不和x比,c說他不和x,z比,請編程序找出三隊賽手的名單。 */main〇chari,j,k/*i是a的對手,j是b的對手,k是c的對手シfor(i=x;iV=^z';i-H)for(]=x;j<Wz;j+0バ*******Sf^2E**********^//if(【?】)/k'k'k'k"k'k'k"k'k'ivkSPN^^'^?火?東?米?^/for貽x';[?];k+0/**********SR^2E**********シ/***********gp^E**********,l>//if(i!=x8&k!=[?])printfCorderisa一%\fb一%\jc~%Np”,i,j,D;答案:.i!づ或i!=j.kWz'或‘z'xk3.i!=k8&j!ぜ或i!=kj!=k*'z’第17題(10.0分)題號:447グ 功能:已知一個數(shù)列,它的頭兩項分別是〇和!,從第三項開始以后的每項都是其前兩項之和。編程打印此數(shù),直到某項的值超過200為止。main〇inti,fl=O,f2=l;for([?];;i-H)printfl);printfぐ刎,⑵;if(f2>20q)break;if(i炒=<DprintfC5);fH=儲/rk'k'k'k'k'k'k'k'k'ksp^j^vk'k'k'k'k'k'k'k'k'k/答案:1).i=lの.200.fl第18題(10.〇分)題號:486グ【程序填空】功能:刪除字符串中的數(shù)字字符。例如:輸入字符串:48CIYP9%則輸出:CIYFE - */#include<stdiah>voidfun([?))whileビdif(ドドヨ(08&(*p<W夕))pH;y^**********gp^E***********/else*s-H=I?];main(){charitem[100];printf(,f\pEnterastringツ;gets(iten);fun(iten);
printfCMlhestring\"%s\"\n",iten);答案:.char*s或charsロ.?中.*s^\0Z或?s=0第19第19題(10.0分)題號:448【程序填空】功能:已知XYZ分別表示い中不同的數(shù)字,編程求出使算式ぶ<幽¥“由亞る軟02成立時XYZ的值,并要求打印該算式。main0intx,y,ぢバ?*バ***sp^2E**********:^/forO=Q[?];x+4)for(r=Qy<lQyH)ifcontinue;forO=Qz<lQz-H)y^'k'irk'k'k'k'k'k"k'kcyp^rpk'k-k'k'k'k'k'k'k"ick/if(?==x[?]ZF=y)continue;/rk'k'k'k火'をタ?'k"k**k/if(1111*(x4-y+2)=[?]+1110*x+z)printf("を%!尸%!%%トが,x,y,2);/k'k'k'k'k'k"k'k'k'k'kSPNJ及火?火?東?火火*^/printfC%H%H%i=%Nn",1”為llll*y,1111*a[?]);exit(Q答案:.x<10或10X.II.1000〇?y或y*10000④.10000*jH-1110*x+z或!0000*y+1110*x+z第20題(10.〇分)題號:416尸 - 【程序填空】功能:計算個人與各科平均成績及全班平均成績,并在屏幕上顯示出來。#defineM5/定義符號常量人數(shù)為、*/#defineN4/定義符號常量課程為4シ#includenstdiah"main〇Iinti,j;voidaver(floatscoMH]№1]);staticfloatscoreMH]№1]={。&85,83,65), 秒&91,89,9次,{72,65,5473,668&75,6a,¢9,6a5a72});aver(scor?;clrscr〇;printfC學生編號課程1課程2課程3課程4 個人平均7り;for(i=Q冋i44){printf。學生%Nf",i+1);收**葭エ^バ?*十**^*★/forG=Qj<[?];j-H)printfC醒!f\t",score[i]皿);printf("\p");)forG=Qj<8?附2;j+0printfprintf(N!課程平均t);forG=Qj<NW;j+f)printf0%score[i]ロ]);printf('\p');getch〇;voidaver(floatsco0Pl-1])inti,j;ィ?バ?*バ?**Sf^2E**********^/for(i=Qi<[?];i-H)forgQj川j+0|sco[i]N4=sco[i]Q];scoMQ]4=scoEi]Q];scoM図4=scoEi]D];scoEi]図[?]N}for(j=Qj小J-H)//9e?バ??せ?**バ*****^/scoM"?】]々MscoMN=scoM図ズ娟'!)答案:.№4或14N或5.M或5/=ホj第21題(10.〇分)題號:488產(chǎn) 功能:有一組基數(shù)值(正整數(shù)),輸入ー個正整數(shù)小于100),問:如果該數(shù)由基數(shù)值相加構成(每個基數(shù)可以重復使用),那么最少可能利用的基數(shù)是多少個。 シ#include<stdiah>#include<stdlib.h>#define M\XSIZE 100#define minQtj) (?<=?? ?)voidmain(voi(J{intnum^KXSIZEI-1];intbaseロ={L3,4};intk=sizeof(hasす/sizeof(int);int"inti,j,MINcharlineQ00];printf(Z===========================り;printfC7i\pBaseValues:ツ;for(i=QiVki-H)printfC%!ッbase[f|);printf('\ri\nYburinputplease->ツ;gets(1inす;n=atoi(1inす;num⑹=Qnun[I]=for(i=ZiV="i-H)メメ?********SPAppt**********/【?】;for(j=aj<k;j-H)if(iXbaseロ])MIN=min¢ium[i-baseH]]+1,MIN;/**********SP/^E**********^Z【?】;printfC\|NMininun=%d",[?]);}答案:.MIN=n.nun[i]=MIN5).nun回第22題(10.〇分) 題號:408尸 【程序填空】功能:輸入兩個整數(shù),求他們的按位與。ツ#include<stdiah>intx,y,z=0,a,b,k=l;scanf &x,&y);v4iile(j<>08^>(J//$r^**<iWf*****Sf^2E?1r^^********3^/A【?】;b=y%i衿んy^rk'k'k'k'k'k'k'k'k'k^p^£J^'k'k'k'k'k'k'k'k*'k/n+【?】;k=k?と[?]C'z=^Nn",2);}答案:D.x/22.a*b*k或a*b*k5.printf第23題(10.〇分)題號:406パ 【程序填空】功能:從鍵盤輸入ー個字符串,將小寫字母全部轉換成大寫字母,然后輸出到ー個磁盤文件“test”中保存。輸入的字符串以!結束。#include"stdiah,,#include<stringh>main。FILE*fRcharstr[100];inti=Qも*'^?也?/if((fp=fopenCtestH,[?]))^<LU)printff'cannotopenthefileXp1);exit0;printf("pleaseinputastring\0ツ;/k'k'k'k'k'k'k'k"k'k'k^pKJ^卞?火火也ヤヤ★★ヤ十/gets([?]);while(str[i]!=!z)y^-k'k'k'k'k'k'k'k'k'k^p^^^'k"k'k'k'k'k'k'k'k'k/if(str[i]>=^a6&[?J)strEi]=str[i]TZfputc(str[i],f?;/失'k'k'k'k'kiF'k'k火spx^vk'k'k'k'k'k'k'k'k'k/fclose([?]);fp=fopenftest1',Hr,r);fgets(str,strlen(sti)-Fl,fpl;printff%s\nu,sti);fclose(f?;}答案:1),nwH2).strみ.str[i]<=z’或/z>=str[i]勺.fp第24題(10.0分)題號:479【程序填空】功能:十個小孩圍成一圈分糖果,老師分給第一個小孩10塊,第二個小孩2塊,第三個小孩8塊,第四個小孩22塊,第五個小孩16塊,第六個小孩4塊,第七個小孩10塊,第八個小孩6塊,第九個小孩14塊,第十個小孩20塊。然后所有的小孩同時將自己手中的糖分一半給左邊的小孩;糖塊數(shù)為奇數(shù)的人可向老師要一塊。問經(jīng)過這樣幾次調(diào)整后大家手中的糖的塊數(shù)都一樣?每人各有多少塊糖?*/main0inti,count=0,aロ1]=Q,1QZ&22,嶼41Q6142a;/vk'k'k'k'k'k'k'k'k'kspx^^c'k'k'k'k'k'k"k'k'k'k/while([?])for(i=l;i<=10;i-H)a[i—1]=a[i—l]/2+a[i]/2;a[10]=a[10]/2-+a[U];for(i=l;i<=10;i-H)y^**********gp^E***********/if([?])a[i]4+;for(i=l;i<10;i+4)if(3[i]!=a[i+1])[?];if(i=iq)break;elsea[0]=0;count-H-;i}printf("count=7^dmmbe4%171",count,aDQ);}答案:1).125.a團沿二13.break第25題(10.0分) 題號:429【程序填空】功能:從讀入的整數(shù)數(shù)據(jù)中,統(tǒng)計大于零的整數(shù)個數(shù)和小于零的整數(shù)個數(shù)。用輸入零來結束輸入,程序中用變量i統(tǒng)計大于零的整數(shù)個數(shù),用變量j統(tǒng)計小于零的整數(shù)個數(shù)。#include<stdiah>mainintk,n,i,j;printf("EnterINTnmber,with0toend7Iり;i=j=QscanfC%1",&rj);/k'k'k'k'k'k/木卡十?S0鼠£卞**k'k'k'kii'k'k'k/if(hXJ)i=[?];十?★★★★/if<h<Q)j=[?l;/^'k*k*k'kivk'k*S^>Xr^^?^ペを達*****/scanf(刎,[?!);答案:1).i+1j+15.&n第26題(10.0分)題號:475パ 【程序填空】功能:下面create函數(shù)的功能是建立一個帶頭結點的單向鏈表,新產(chǎn)生的結點總是插入在鏈表的末尾。輸入〇代表結束,單向鏈表的頭指針作為函數(shù)值返回。 …… V#include<stdiah>#defineLENsizeof(structstudent)structstudent{longnun)structstudent*next;卜structstudent*creat0(structstudent*head=NJLL,*tai1;longnurqinta;も*'^?也?/tai1=([?])malloc(UN;printfCfpleaseinputdat^y!ツ;doscanfC%ld",&nun);//$r^**<iWf*****Sf^2E?1r^^********3^/y^vk'k'k'k'k"k'k'k**^p^^("k'k"k'k'k'k'k*'k'k/if([?])head=tai1;elsetail=tail->next;tail->mnr=nLiTjtail->next=(struct1istmalloc(LEN;|elsetail->next=^MLL;}while(hurrf=Q;return(head);main〇|structstudent*rp=creat〇;printfCyouinputisXn11);while(p)printffH>nuT);p=p->next;}}答案:.structstudent*.nunl=0或Q=nun.head=NULL第27題(10.0分)題號:437產(chǎn) 【程序填空】功能:建立一個如下的二維數(shù)組,并按以下格式輸出。1000101010001000101010001#includeHstdiah"voidmain(inta[5]回=紅,*p0,i,j;for(i=Qi<5;i-H)/k'k'k'k'k"k'k'k'k'k'kqpMT'k'火"k"k"k'k'k'k'k'k'k/p□=[?];for(i=Qi<5;i-H)^$nt**W******Sf^2E**********^/*(1?]+0=1;/rkirk'kii'k火'k'k'kSpNJ^^*^^宗宗夫★火火火/*<pLi]+5-([?l))=1;for(i=Qi<5;i-H)for(j=Qj<5;j-H)printfC%d",p[i]□);/^r**********gpy^E**********,l7/答案:1).&a[i]吻25.P國i+1或1+i.putchar(5);第28題(10.0分)題號:445產(chǎn) 【程序填空】功能:編程求任意給定的n個數(shù)中的奇數(shù)的連乘積,偶數(shù)的平方和以及〇的個數(shù),n通過scanf〇函數(shù)輸入。main0intr=l,s=0,t=0,n,a,i;printf("n=1);scanf&rj);for(i=l;i<=n;i-H)printfscanfC%i",[?]);パメ?次火火?**太太ミ丑即が'^^宗?火?太火太/y^'kirkit'k'k'k"ki<'k^p^Q^k'k'k'k'k"k'k'k"k'irky/elseif(3!=€D/k'k'k'k"k'k'k'k'k'k'kspx^卞'k'k'k'k'k'k'k'k**/si?】;elset-Fhprintf("K%1s=%tt=%i\n",r,s,t);答案:1).&a2),加.r*第29題(10.。分)題號:25尸【程序填空】功能:以下程序的功能如圖Do★★★*/main〇floatx,£scanf(%",8oi);/k'k'k'k'k'k'k'k'k^'kSpN^vk'ivk'k'k'k'k'k'k*/if(x<Q)[?];//$c?バ??バ?**SR^E**********^/7elseif([?!)elsef=sin⑨+5;y^*'k'k'k'k'k'k*'k'k<^)p^^rk'k'k'k'k'k'k'k'k'k/printfy=%f\nH,[?!);答案:1).#include,lmath.h"或#include<inath.h>3.K=5或5n=x或x<6或6>x或x>=O&8<x<=5或O5=x8&x<=5或yO=08&5>=x,或O<^48&5K或!95).x,f第30題(10.〇分)題號:446個 【程序填空】功能:編程求某年第n天的日期。用數(shù)組表示月天數(shù)。main0inty,n)f,店inta。用={31,2&31,30,31,30,31,31,30,31,3Q31};printf("y,n=');scanfC%1%j",&y,&n);/失火?火?火央/冋ネ=o幽%oa=o【?】靜oo=qバ?*バ***sp^2E**********:^/a〇〇[?)f;if(pelI|ri>3654-f)printf("error!\p');exit?;for(n=l;m[?]afn-1];n-?=a£n-l],mH);printf d=%Ni",y,n)n>;答案:.II.4*=或=a+.>第31題(10.〇分)題號:481尸 - 【程序填空】功能:ー個自然數(shù)被8除余1,所得的商被8除也余1,再將第二次的商被8除后余7,最后得到ー個商為る又知這個自然數(shù)被17除余4,所得的商被17除余I5.最后得到ー個商是a的2倍。編寫程序求這個自然數(shù)。 ソmain〇{inti,n,a;i=0;while(1)if(i泓=Dn=i/8;
if0=1)n=^8;y^rk'k"k"k'k'k-kirk'kQp^Q^kicic'k'k-k'k-k-k-k'k^/if妙合=力[?];if(%7=¢n=i/47;if/!7=1》n=n/l7;printf("result=%Ni",i);^?c**********SP^2E**********^/バ*****SP^2E**********^//答案:1).》.break3.i卄或?H-i或i=i+l第32題(10.0分) 題號:461【程序填空】功能:從鍵盤輸入ー個字符串,將小寫字母全部轉換成大寫字母,然后輸出到ー個磁盤文件“test”中保存。輸入的字符串以!結束。 ■*/#includenstdiah"main0FILE*fpcharstr[100],filename[10];inti=Qif((fp=fopenCtest'1,,,wl))=NJLI){printfぐcannotopenthefile\i1);exit?;printf(Hpleaseinputastring5);gets(sti);while([?])if(stra8&str[i]<^z)fputc(str[i],fp);fclose(f?;//9c*****バ***SP^2E**********'5^Zfp=fopen("test",[?]);fgets(str,strlen(sti)+1,fp);printf(%\p",str);fclose(fp);)答案:1).str[i]!=’!'2J.str[i]=str[i]—32或str[i]=str[i]—325)."r"或"wr"或"wr+"第33題(10.0分)題號:21六 【程序填空】功能:將一個字符串中的前N個字符復制到ー個字符數(shù)組中去,不許使用strcpy函數(shù)。 Vmain〇{charstrl[80],str2[80];inti,風/k'k'k'k"k'k'k'k'k'k'kヾpM'Fk'k'k'k'k'k'k'k'k'k'k/gets([?]);scanfC%i",&rj);バ??バ?**Sp^2E**********^/for(i=Q[?];i-H)せ*******SF^2E**********^/[?];/rk'k'k'k'k'k'k'k'k'kspxj^c"k'k'k'k'k'k'k'k'k'k/printf。%久p”,str》;答案:.strl.i<h或ri>i或iv=n-l或n-l>=istr2[i]=strira或?(str2+i),(strl+i)或?(str2+i)=strl[i]或str2[i]=^(strl+i)4>.str2回/7r或str2[i]」7r或str2冋=0或str2[i]=0或?(str2-M=\pz或?(str2+i)=\〇"或?(stHfj)=0或?(str24-i)=0第34題(10.0分)題號:13グ 【程序填空】功能:產(chǎn)生并輸出楊輝三角的前七行。112113311464115101051161520156main〇intaSS;inti,j,k;for(i=Qi<7;i-H)a[i]吻=1;for(i=2;i<7;i-H)/rk'k'k'k'k'k十太**SpNja'k'k*'k*火'k***/forG=l;j<l?l;j+0十'kirk***'aLi]Q]=[?];for(i=Qi<7;i-H)/k十十十十十十十?十十國》十十十十十十十十十十/for(j=Q[?];j-H)printfC%5d",aロコU]);printfONツ;答案:.a國[i]=li5).aLi-1]K^Ci-1]D-l]或aLi-1]LH]y[i-1]54).j<=i或i>=j或j<i+l或i+l>j或j—l<i或i>j—1第35題(10.〇分)題號:424【程序填空】功能:輸出結果為:去****main0staticchar[?]=]火/ア「セ「依「火};inti,j,kcharspace=for(i=Qi<5;i~H)printfC\n");forG=l;j<=3*i;j-H)printf("%lc",[?]);^^**********5^^***********/for(t=Qk<[?];leH)printf0%c”,a図);)printf}答案:1).a0或a0T).space或''"5或=4第36題(10.〇分)題號:485個 【程序填空】功能:統(tǒng)計子字符串substr在字符串str中出現(xiàn)的次數(shù)。例如:若字符串為"aaasIkaaas".子字符串為"as",則應輸出2若字符串為"asasasa"J子字符串為"asa",則應輸出3 */#include<stdiah>funfchar*substr,char*stp
inti,j,k,nin^Qfor(i=05str[i];i-H)for(j=i,k=Qsubstr[k]=str[j];k-H;j-H)if(substrE[?l]=\4/)numFhreturnnurnmain〇charstr[80],substr[BO];printf(HInputastring");gets(sti);printf("Inputasubstring');gets(substi);printfC%Nn",{?]);答案:D.2).breakS).fun(substr,sti)第37題(10.0分)題號:411【程序填空】功能:有n個人圍成一圈,順序排號。從第一個人開始報數(shù)(從1到3報數(shù)),凡報到3的人退出圈子,問最后留下的是原來第幾號的那位。#definenmax50mainj)inti,k,n)n,numfjinaW,printff'pleaseinputthetotalofnumbers:ツ;scanf('%!",&rj);p=qitnj卞?十?^十ヤ★★ヤ十/for(i=Q[?];i+9/rk'k'k'k'k'k'k宗'k'kSpX^rkidt'k'k'k'kKk'k/?的)=【?】;vA\ile1)/rk'k'k*★火★火?k'kSPM^rk★火★★火★'if([?]1=0)ヒ咔*(pH-i)=QmH;i+hif(ifi曲}/^**********SF^3E********:■while((?])pH;printfC%jisleft\n",*p);)答案:.i<i!或ri>i.i+1或i+1.?什?;?(p+i)④.*p=0或*p=0第38題(10.〇分)題號:35尸 【程序填空】功能:計算并輸出high以內(nèi)最大的10個素數(shù)之和,high由主函數(shù)傳給fun函數(shù),若high的值為10Q則函數(shù)的值為732, -*/#include<toniah>#lnc-ude<stdiah>#Include<fmrhh>intfun二nthigh)宀intsurnuQ0=02Lyes;while(今igh>=7<8&(【.二))宀yesUI;forGHZj-H-)/k'k'k-k'k'k'k'k'k'k'ko^p^T'y^*****キ*キ'if(【.二)宀yes=Qbreak;一if々es)宀sun-M11S-i一high—;一【二;一main()宀clrscr();答案:1).n<10或10nか.high%j=0或!(high%j)?returnstm或return(sm)第39題(10.〇分)題號:28【程序填空】功能:將十進制數(shù)轉換成十六進制數(shù)。#includenstdiah"#include"stringh”mainjfinta,i;chars120];printf(Hinputainteger\p');clOJ6(s,a);/ck'k'k'k'k'k'k'k'k'kSONja'k'k'k'k'k?十**'k/for([?];ixQi—)printf(1%",sLi]);printfヘツ;clQ_J69harp0,int5intj,i=QWiile([?])ifG>=08&j<H)***'elsep[i]=j+5%iH/k'k'k'k'k'k'k'k'k^'kspx^vk'k'k'k'k'k'k'k'k*/[?];答案:.i=strlen(s)—!或i=^l+strlen(s).b>0或(Xb或b!=O或O!=b或b3.p[i]=j+'?或p[0=j+48ng?什i)=j+'(/或*>i)=j+484).pLi]=U或p[ロ=0或 pLi!寸tILし或 ?什i)=7Z或?(p-Fi)=0或*M)^LLL第40題(10.0分)題號:414【程序填空】功能:通過函數(shù)的遞歸調(diào)用計算階乘。longpower(int巾longf;if(jt>D/ck'k'k'k'k'k'k'k'k'kSP葭段?k興女?k'k'k'k'k'k/f=[?l;elseM;return(0;}main0{int弭longXprintf(Hinputainteagernumber\o,r);scanfC%!",[?]);//$rs*nWc**'^***SP^'P^**15Wr******/printff%l=%ld\n",n,[?]);getch〇;答案:.power(p—1)*n或power(n—1)*n或n*power(ji—1).&n.power?或y第41題(10.〇分)題號:454個 【程序填空】功能:三角形的面積為:aremqrt(s*(s?團?(s-tj)*(s-c)).其中,hc為三角形三條邊的長。定義兩個帶參數(shù)的宏,ー個用來求s,另一個用來求area,編寫程序,在程序中用帶參數(shù)的宏求面積are&ツ#include"math,h"#1?]s&y,かO+y+^/2#define?REA(s,x,y,2)sqrt(s*(s—力*(s-^*(sf)main〇floata,b,Gs,area;printf("a,b,日);/ck'k'k'k'k'k'k'k'k'kSONja'k'k'k'k'k?十**'k/scanf &a,[?],&c);if 0a8&cH~a>tj)/rk'k'k'k******S=I?1;are后【?】;printf("area=%f\n",area);答案:.define.&b.SRh。④.闋EA(s,a,b,0第42題(10.0分)題號:6【程序填空】功能:以下程序是用選擇法對10個整數(shù)按升序排序。[7]main0inti,j,k,t,aN;for(i=Qi-H)for(j=i+l;[?];j+9if@ロ]Va図)仁;/k'k'k'k'k*k*k*kS^>C^'k'k'k*k*k'k*k/t=^a[i];a[i]』因;aR=t;}}printf("outputthesortedarray\pツ;for(i=Qi<MM-l;i+4)printfC%d",a國);printf(Z');答案:.#defineN102),仁i&.j<N或N>j或j<=N-l或N-l>=j④.k!=i第43題(10.。分)題號:417【程序填空】功能:利用全局變量計算長方體的體積及三個面的面積。intsLs2,s3;intvs(inta,inthintq)intv;sl=a*Uy^rk'k'k'k'k'k'k'k'k'k^p^^^c"k'k'k'k'k'k'k'k'k'k/s2=[7];s3=a*qreturnv;main〇intv,1,whclrscr0;printfC\pinputlength,widthandheight:ツ;/失常spxnrk'k'k'k'k'k'k'k'k'k/scanf('%%%1n,[?],&5^&h);I?1;printf sl=%js2^ds3=%d\n",v,si,s2, ;getch)答案:1),a*b*c或a*b*c.b*c或b*c.&1.vs(1,w?或vs(1,w,h)第44題(10.。分)題號:30片 【程序填空】功能:輸入字符串,再輸入一個字符,將字符串中與輸入字符相同的字符刪除。#includeHstdiah1'voidfunCharaQ,charq)inti,j;//9e?バ??せ?**SJ^Y2E**********^/for(i=j=Q[?];i-H)if@[i]!=Oa[j+6=a[i];//$C**3Wf**W^***SP^~rp3lf**'5lr^******/main0chara[2Q],cc;gets團;/rk'k'k'k'k'k'k'k'k'kspxj^c"k'k'k'k'k'k'k'k'k'k//^?k'k'k'k'k'k'k'k'k'kSpN^^'k'k'k'k'k'k'k'k'k'k/puts@;答案:1).aLi]!='?或a[i]或aロ]!=NLLL3.a=或a[j]與!エe或aLj]=O).cc=^etcharj!或scanf("%:",&cc).funQcc)第45題(10.〇分)題號:407尸 - 【程序填空】功能:有五個學生,每個學生有3門課的成績,從鍵盤輸入以上數(shù)據(jù)(包括學生號,姓名,三門課成績),計算出平均成績,設原有的數(shù)據(jù)和計算出的平均分數(shù)存放在磁盤文件"stud"中。#includenstdiah"structstudentIcharnum⑹;charname囲;intscore[3];floatavi;}stu〇;main${inti,j,sun)FILE*fp/*inputシfor(i=Qi<5;i+0{printfpleaseinputNa%iscore\nH,i);printfC'stuNaツ;scanfstu[i].nun);printf("name:ツ;scanff%",stu[i].name);surn=Q火太火火★火★水*/for(j=Q[?];j+0printff'score%i",j+1);scanf&stu[i].scoreG]);/^?W^C*******;^^^^********"^/sumQstu[ロ.[?];stu[i].avi=surr/3.?fp=fopen("stud","wツ;/k'k'k'k'k'k'k'k'k^'kSpN^vk'ivk'k'k'k'k'k'k*/for(i=0ji<5;[?])if(fwrite&stu[i],sizeof([?]),1,fp)!=1)printf("filewriteerroi\n');fclose(fp);)答案:D.j<3或劃.score[j].i44?或4-f-i或i=i+l.struetstudent第46題(10.0分)題號:471【程序填空】功能:給出?個正整數(shù),找到?組連續(xù)的數(shù),使之累加和等于給定的正整數(shù)。輸出存在多少組這樣連續(xù)的數(shù),及每組的左右邊界。例如:15=1+24344+5所以結果有3組值分別是1ぶ5,住728#include<stdiah>#include<stdlitxh>voidmain(yoi(i[longleft,right;longsun;longGIVEblintcount=Qcharline[100];printf('Consecutivesuntoafixedgivennumber');printf(Z ゝ3');printf(,f\nYdurnumber(>0)please >');gets(line);GIVEN=atol(1ine);for(sum=0,right=1;sunVGIVENsum4=right,right-H)for(left=1,right~;left<=GIVEbJ^)if(sum>GIVH9sum-=left;/佻:'k'k'k'k'k'k'k'kick/elseif(sum=GIVENprintfCN^ld=sumfrcm%ldto%ldH,GIVENleft,right);尸**********Sfi^E**********シ[?1;sun4=right;}iffcount>。printf reare%isolutionsintotal.",count);elseprintfC^xfiXpSorry,thereisNDsolutionatal1.');}答案:.left+l?或left=left+l或-H-left.count-H?或count=count-H?或4+count或count=count4-lright-H?或right=right-H?或4+right或right=right-f-l第47題(10.0分)題號:451盧 【程序填空】功能:編程求任意給兩個日期(Y0年M)月DO日和Y1年M月D1H)相差的天數(shù)。main〇intyl,ml,dl,y2,m2,d2,n,i;printf(Hyl,ml,dl—);scanf。%%dH,&yl,&nl,&dl);iffnl<l||ml>12||dl<l||dl>[?])exit(Q);printf(Hy2,m2,d2=,r);scanf(1%],%j,%1”,&y2,&r)2,&dの;iffn2<l||m2>12||d2<l||d2>(?])exit(Q);iffyl>y21Iyl=y28&nl>n2yl=y28&nl^^n28&dl>d2)つ!;ylラスy/n=ml;ml=m2;m2=r^n=dl;dl=d^d2=(xelsen=yend(yl,ml,dl)+[?];/rk'k'k*k*'k'k'k'kSP魔央常火宗火宗宗火★/for(i=[?J;i<yZi+0rH?=3654"f(i);printf('%i%i%i~>%1%i%± yl,ml,dl,y2,m2,d2,q);intf(inty)[return嫡=05¢?%!()。=0||%00=Q);)intmday(inty,intn){return(31—((n=^+(n=^)+(n=^+(n=l1))—0-fゆ)*(n=2));}intyday(inty,intn)int巾(return(d+31*((ii>l)+ 4-(n>5)4- +(ii>?+(ii>lQ))+30*((rl>4)+ +(n>^+6>11))+Q&Hゆ)*ゆか);}intyend(inty,int卬intd)(return065+f(y)づday(y,it)(D);}答案:.mdayfyl,ml).mday62m3.yday(y2,m2,dのyl+1或1+yl第48題(10.〇分)題號:398グ 【程序填空】功能:打印出如下圖案(菱形)***'k'k'k'Jvk'k"k'k'k"k'irk?k'k'k'k'k***■k 一?/#include<stdiah>main〇{inti,j,kfor(i=Q[?];i-H){for〇=Qj<=4—i;j-H)printfC");forgl;ヒ=【?】5leH)printfC*1);printffKn1);パ*****バ*?仁12^^**********^^/ford?];j<3;j-H)(fork=Qk<j-F3;k-H)printf("");for¢¢=0;k<5-2*j;k-H)printf("*');printf('\n");答案:.i<=6或i<4或3>=i或4>i.2*i+l或i*2+l或1+2*i或l+i*2.j=0第49題(10.〇分)題號:402尸 - 【程序填空】功能:輸入三個整數(shù)芻y,ろ請把這三個數(shù)由小到大輸出。 -*/int\y,z,t;scanf &x,&y,&z);//9c*****バ***SP^2E**********'5^Zif僅動{【?】}/k'k'k'k'k'k'k'k'k^'kSpN^vk'ivk'k'k'k'k'k'k*/if出ガ{[?]}^f**********SRYI?1r**********5^if&*){[?]}printf("smal1tobig%d%d%tW',%y,力;答案:D.efK2).t=z;z==x;x=t;5.t=y;y=^;z?=t;第50題(10.〇分)題號:489【程序填空】功能:Sequence是ー組由〇和1組成的數(shù)列,它定義如下:<h—seq>=0<h—seq>=1<h—secp><h-secp>利用函數(shù)檢測輸入的字符串是否是いequence數(shù)列 シ#include<stringh>冊efineYES1#defineND0inth_sequencefcharx□)intlength=[?];intcount;inti;forfcount=1,i=Qcount!=0i<lengthi-H)switch僅[i1)(case’〇":count~;break;case'lz:count44;break;default:returnN2)}return[?]8&i>=length;#include<stdiah>voidmainfyoicj)charline[100];printfCKriXpInputastringof0and1―>ツ;
gets(Iinq);/vk'k'k'k'k'k'k'k'k'kspx^^c'k'k'k'k'k'k"k'k'k'k/if([?]YE9printfInputisaHsequence***");elseprintf0。?**InputisN3raHsequence****);答案:1).strlen⑨》.count=0h_sequence(line)第51題(10.0分)題號:403【程序填空】功能:輸出9*9口訣。mainQinti,j,result;printfC\p');//9e?バ??せ?**SJ^Y2E**********^/for(i=l;[?];i-H)//$n*f**'i^*****SPA/r''P^oWf********/for(j=l;jVIa[?])result=i*j;バ*******Sf^2E**********^^Zprintf("%di%l=%-3d",i,j,[?!);}printf('\n");))答案:1).i<10或100i4.j-H?或+H或j與+13.result第52題(10.〇分) 題號:421盧 【程序填空】功能:輸入學生成績并顯示。 V#include<stdiah>structstudentcharnurber⑹;
charname⑹;intscore[3];}stu[2];voidoutput(structstudentstuC3);i,jfor(i=0ji<2;[?])printf。請輸入學生%!的成績:\p",i+D;printf。學號:ツ;scanf("%s",[?].number);printf(1姓名:ツ;scanfC%",stu[i].namq);forG=Qj<3;j+0printf。成績%1 ",j+1);***'scanf。%!",[?]?score□);output(stij);voidoutput(structstudentstu②)inti,j;printバ學號姓名成績1成績2成績へg;for(i=Qi<^i-H)[?]("%-6s%-6s",stu[i].nutrber,stu[i].nam^;for(j=Qj<3;j-H)printfC%-8d",stu[i].score[〇);printf「5);}}答案:.i卄或++i或i=i+l.&stu[i].&stu[i]④.printf第53題(10.〇分) 題號:438尸 【程序填空】功能:求出ニ維數(shù)組中的最大元素值。#include"stdiah"inta図図={{1,3,5,71, {15,17,34,12}};バ??バ?**Sp^2E**********^/printf(^xvalueis%d\p",[?]);max_value n,arra^/vk'k'k'k'k'k'k'k'k'kSPPCff^a^^?女火太/intIT)n,[?]inti,j,max;max=array吻吻;for(i=Qi倒i-H)for0=Qj-H)/^'k'k'k'k'k'k'k'k'k'kspx^t'k'k'k'k'k'k'k'kick/if(nax<array[i][j])[?];return(na力;)答案:.max_value0,4a)與.array〇⑷或array⑶⑷3.ma??=array田[j]第54題(10.〇分)題號:415ぐ 【程序填空】功能:數(shù)組名作為函數(shù)參數(shù),求平均成績。floataver(floata[])/定義求平均值函數(shù),形參為ー浮點型數(shù)組名リinti;floatav,s=a⑹;for(i=l;i<5;i-H)s4=[?]Lfl;av=^/5;/*k'k'k'k*k*'k*SpN
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯(lián)系上傳者。文件的所有權益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會有圖紙預覽,若沒有圖紙預覽就沒有圖紙。
- 4. 未經(jīng)權益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫網(wǎng)僅提供信息存儲空間,僅對用戶上傳內(nèi)容的表現(xiàn)方式做保護處理,對用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對任何下載內(nèi)容負責。
- 6. 下載文件中如有侵權或不適當內(nèi)容,請與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準確性、安全性和完整性, 同時也不承擔用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。
最新文檔
- 教育行業(yè)在線教育平臺的課程評價體系方案
- 造價咨詢合同
- 2025年天津貨運從業(yè)資格證模擬試題答案解析大全
- 2025年寧德貨物運輸駕駛員從業(yè)資格考試系統(tǒng)
- 電子消費券采購合同(2篇)
- 電力電量分配合同(2篇)
- 電池焊接維修合同(2篇)
- 2024年高考歷史二輪復習“12+2+3”專項練第46題選做題專練
- 2024-2025學年四年級語文上冊第五單元19奇妙的國際互聯(lián)網(wǎng)教案2蘇教版
- 2024-2025學年高中化學第二章化學反應與能量第二節(jié)化學能與電能2發(fā)展中的化學電源課時訓練含解析新人教版必修2
- 民辦幼兒園務工作計劃
- 2025年華僑港澳臺生聯(lián)招考試高考地理試卷試題(含答案詳解)
- 內(nèi)鏡室院感知識培訓課件
- 2025年市場拓展工作計劃
- 2025年八省聯(lián)考云南高考生物試卷真題答案詳解(精校打印)
- 2020-2024年五年高考歷史真題分類匯編(山東)專題15 中國古代史(原卷版)
- 中國革命戰(zhàn)爭的戰(zhàn)略問題(全文)
- 《數(shù)學歸納法在中學解題中的應用研究》9000字(論文)
- (房屋建筑部分)工程建設標準強制性條文版
- 《大學英語四級詞匯大全》
- 倉庫管理培訓課件
評論
0/150
提交評論