北師大版數(shù)學(xué)七年級(jí)下冊(cè)整式的除法（提高）鞏固練習(xí) (含答案)

PAGE【鞏固練習(xí)】一.選擇題1.（2020?廣元）下列運(yùn)算正確的是（）A．（﹣ab2）3÷（ab2）2=﹣ab2 B．3a+2a=5a2C．（2a+b）（2a﹣b）=2a2﹣b2 D．（2a+b）2=4a2+b22．若SKIPIF1<0，則SKIPIF1<0值是()．A.SKIPIF1<0＝SKIPIF1<0＝1 B.SKIPIF1<0＝SKIPIF1<0＝2C.SKIPIF1<0＝1，SKIPIF1<0＝2 D.SKIPIF1<0＝2，SKIPIF1<0＝13．SKIPIF1<0的結(jié)果是()．A.8SKIPIF1<0 B.－8SKIPIF1<0 C.2SKIPIF1<0 D.8SKIPIF1<04．下列計(jì)算中錯(cuò)誤的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<05.已知SKIPIF1<0與一個(gè)多項(xiàng)式之積是SKIPIF1<0，則這個(gè)多項(xiàng)式是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<06.計(jì)算SKIPIF1<0除以SKIPIF1<0后，得商式和余式分別為（）A．商式為3，余式為SKIPIF1<0B．商式為3，余式為8C．商式為3SKIPIF1<0＋8，余式為SKIPIF1<0D．商式為3SKIPIF1<0＋8，余式為0二.填空題7.（2020?寶應(yīng)縣校級(jí)模擬）計(jì)算：（21x4y3﹣35x3y2+7x2y2）÷（﹣7x2y）=______________.8.一個(gè)長方形的面積是（SKIPIF1<0）平方米，其長為（SKIPIF1<0）米，用含有SKIPIF1<0的整式表示它的寬為_______米.9.(1)已知SKIPIF1<0＝3，SKIPIF1<0＝2，SKIPIF1<0__________．(2)已知SKIPIF1<0＝6，SKIPIF1<0＝8，SKIPIF1<0___________．10.已知A是關(guān)于SKIPIF1<0的四次多項(xiàng)式，且A÷SKIPIF1<0＝B，那么B是關(guān)于SKIPIF1<0的_______次多項(xiàng)式．11.若MSKIPIF1<0，那么整式M＝____________．12．若SKIPIF1<0＝3，SKIPIF1<0＝6，SKIPIF1<0＝12，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0之間的數(shù)量關(guān)系是________．三.解答題13．先化簡，再求值：SKIPIF1<0，其中SKIPIF1<0＝2，SKIPIF1<0＝－3．14．（2020春?北京校級(jí)月考）（﹣4a3﹣7a3b2+12a2b）÷（﹣2a）2．15.是否存在常數(shù)SKIPIF1<0、SKIPIF1<0使得SKIPIF1<0能被SKIPIF1<0整除？如果存在，求出SKIPIF1<0、SKIPIF1<0的值，否則請(qǐng)說明理由.【答案與詳解】一.選擇題1.【答案】A；【詳解】解：A、（﹣ab2）3÷（ab2）2=﹣a（3﹣2）b（6﹣4）=﹣ab2，故本選項(xiàng)正確；B、3a+2a=（3+2）a=5a，故本選項(xiàng)錯(cuò)誤；C、（2a+b）（2a﹣b）=4a2﹣b2，故本選項(xiàng)正確；D、（2a+b）2=4a2+4ab+b2，故本選項(xiàng)錯(cuò)誤；故選：A．2.【答案】A；【詳解】SKIPIF1<0，所以SKIPIF1<0，SKIPIF1<0，SKIPIF1<0＝1.3.【答案】A；【詳解】SKIPIF1<0.4.【答案】D；【詳解】SKIPIF1<0.5.【答案】C；【詳解】這個(gè)多項(xiàng)式為SKIPIF1<0.6.【答案】A；【詳解】SKIPIF1<0×商式＋余式＝SKIPIF1<0.二.填空題7.【答案】﹣3x2y2+5xy﹣y；【詳解】解：原式=21x4y3÷（﹣7x2y）﹣35x3y2÷（﹣7x2y）+7x2y2÷（﹣7x2y）=﹣3x2y2+5xy﹣y．8.【答案】（SKIPIF1<0）；【詳解】根據(jù)長方形的寬＝面積÷長，再利用整式的除法求解即可．9.【答案】(1)SKIPIF1<0；(2)SKIPIF1<0；【詳解】SKIPIF1<0；SKIPIF1<0.10.【答案】三；11.【答案】SKIPIF1<0；【詳解】M＝SKIPIF1<0.12．【答案】SKIPIF1<0；【詳解】SKIPIF1<0，所以SKIPIF1<0.三.解答題13.【詳解】解：原式＝SKIPIF1<0＝SKIPIF1<0＝SKIPIF1<0當(dāng)SKIPIF1<0＝2，SKIPIF1<0＝－3時(shí)，原式＝SKIPIF1<0.14.【詳解】解：（﹣4a3﹣7a3b2+12a2b）÷（﹣2a）2=（﹣4a3﹣7a3b2+12a2b）÷4a2=﹣a﹣ab2+3b．15.【詳解】解：設(shè)SKIPIF1<0SKIPIF1<0由等式左右兩邊對(duì)應(yīng)系數(shù)相等可得：SKIPIF1<0,SKI